利用C语言求4阶方阵主、副对角线上的元素之积。
时间: 2023-05-20 19:02:41 浏览: 150
可以使用以下代码来求解:
```c
#include <stdio.h>
int main() {
int matrix[4][4] = {{1, 2, 3, 4},
{5, 6, 7, 8},
{9, 10, 11, 12},
{13, 14, 15, 16}};
int mainDiagonalProduct = 1, secondaryDiagonalProduct = 1;
for (int i = 0; i < 4; i++) {
mainDiagonalProduct *= matrix[i][i];
secondaryDiagonalProduct *= matrix[i][3 - i];
}
printf("The product of elements on the main diagonal is %d\n", mainDiagonalProduct);
printf("The product of elements on the secondary diagonal is %d\n", secondaryDiagonalProduct);
return 0;
}
```
这个程序会输出主对角线和副对角线上的元素之积。
相关问题
用c语言分别写出n阶方阵a的主对角线元素和,副对角线元素之和,非对角线元素之和
下面是用 C 语言实现的代码:
```c
#include <stdio.h>
int main()
{
int a[10][10], i, j, n, sum1 = 0, sum2 = 0, sum3 = 0;
printf("Enter the order of matrix: ");
scanf("%d", &n);
printf("Enter the elements of matrix:\n");
for(i = 0; i < n; i++)
{
for(j = 0; j < n; j++)
{
scanf("%d", &a[i][j]);
}
}
// 计算主对角线元素之和
for(i = 0; i < n; i++)
{
sum1 += a[i][i];
}
// 计算副对角线元素之和
for(i = 0, j = n - 1; i < n && j >= 0; i++, j--)
{
sum2 += a[i][j];
}
// 计算非对角线元素之和
for(i = 0; i < n; i++)
{
for(j = 0; j < n; j++)
{
if(i != j && i + j != n - 1)
{
sum3 += a[i][j];
}
}
}
printf("Sum of main diagonal elements: %d\n", sum1);
printf("Sum of secondary diagonal elements: %d\n", sum2);
printf("Sum of non-diagonal elements: %d\n", sum3);
return 0;
}
```
假设输入的方阵为:
```
1 2 3
4 5 6
7 8 9
```
则输出结果为:
```
Enter the order of matrix: 3
Enter the elements of matrix:
1 2 3
4 5 6
7 8 9
Sum of main diagonal elements: 15
Sum of secondary diagonal elements: 15
Sum of non-diagonal elements: 28
```
用c语言编写程序,求一个方阵中主对角线和副对角线元素和
好的,以下是用 C 语言编写的程序,可以计算一个方阵中主对角线和副对角线元素和。
```c
#include <stdio.h>
int main() {
int n;
printf("请输入方阵的阶数 n:");
scanf("%d", &n);
int a[n][n], i, j;
int sum1 = 0, sum2 = 0;
// 输入矩阵的元素
printf("请输入矩阵的元素:\n");
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
printf("a[%d][%d] = ", i, j);
scanf("%d", &a[i][j]);
}
}
// 计算主对角线元素和
for (i = 0; i < n; i++) {
sum1 += a[i][i];
}
printf("主对角线元素和 = %d\n", sum1);
// 计算副对角线元素和
for (i = 0; i < n; i++) {
sum2 += a[i][n-i-1];
}
printf("副对角线元素和 = %d\n", sum2);
return 0;
}
```
运行程序后,输入方阵的阶数和元素,程序会计算出主对角线和副对角线的元素和,并将结果输出。
阅读全文