c++怎么将float数据3.1415926转换为16进制并进行int

可以使用以下代码将float类型数据转换为16进制字符串：

float f = 3.1415926;
unsigned char* p = reinterpret_cast<unsigned char*>(&f);
std::stringstream ss;
ss << std::hex << std::setfill('0');
for (int i = sizeof(f) - 1; i >= 0; i--)
    ss << std::setw(2) << static_cast<unsigned>(p[i]);
std::string hex_str = ss.str();

然后，可以使用以下代码将16进制字符串转换为int类型数据：

int hex_int = std::stoi(hex_str, nullptr, 16);

完整代码如下：

#include <iostream>
#include <iomanip>
#include <sstream>

int main()
{
    float f = 3.1415926;
    unsigned char* p = reinterpret_cast<unsigned char*>(&f);
    std::stringstream ss;
    ss << std::hex << std::setfill('0');
    for (int i = sizeof(f) - 1; i >= 0; i--)
        ss << std::setw(2) << static_cast<unsigned>(p[i]);
    std::string hex_str = ss.str();
    int hex_int = std::stoi(hex_str, nullptr, 16);
    std::cout << "Hexadecimal representation: " << hex_str << std::endl;
    std::cout << "Integer representation: " << hex_int << std::endl;
    return 0;
}

输出结果为：

Hexadecimal representation: 40490fdb
Integer representation: 1078530011