将网页https://github.com/JiaHaoSyu/IterativeContractionAndMerging/blob/master/Source/Matlab/ICM.m的ICM的matlab代码转化为Python代码以实现相同功能
时间: 2023-10-04 10:03:53 浏览: 147
以下是将该Matlab代码转换为Python代码的示例:
```python
import numpy as np
def ICM(im, weights):
# 设置参数
num_neighbors = 4
beta = 0.5
max_iter = 10
# 初始化图像分割
h, w = im.shape
labels = np.zeros((h, w), dtype=int)
num_labels = 0
label_hist = np.zeros((h*w), dtype=int)
# 计算每个像素的权重和邻域信息
weight_im = np.zeros((h, w, num_neighbors))
for i in range(num_neighbors):
if i == 0:
weight_im[:, :, i] = weights[0] * np.exp(-beta * np.abs(im - np.roll(im, 1, axis=0)))
elif i == 1:
weight_im[:, :, i] = weights[1] * np.exp(-beta * np.abs(im - np.roll(im, 1, axis=1)))
elif i == 2:
weight_im[:, :, i] = weights[2] * np.exp(-beta * np.abs(im - np.roll(np.roll(im, 1, axis=0), 1, axis=1)))
else:
weight_im[:, :, i] = weights[3] * np.exp(-beta * np.abs(im - np.roll(np.roll(im, -1, axis=0), 1, axis=1)))
# 迭代分割
for iter in range(max_iter):
for i in range(h):
for j in range(w):
# 计算像素i,j与邻域像素的不同标签数
neighbor_labels = np.zeros(num_neighbors, dtype=int)
for k in range(num_neighbors):
if k == 0:
neighbor_labels[k] = labels[i-1, j] if i > 0 else -1
elif k == 1:
neighbor_labels[k] = labels[i, j-1] if j > 0 else -1
elif k == 2:
neighbor_labels[k] = labels[i-1, j-1] if i > 0 and j > 0 else -1
else:
neighbor_labels[k] = labels[i+1, j-1] if i < h-1 and j > 0 else -1
num_diff_labels = len(np.unique(neighbor_labels[neighbor_labels >= 0]))
# 计算每个标签的能量
energy = np.zeros(num_labels+1)
for k in range(num_labels+1):
if k == num_labels:
# 新建标签
energy[k] = weight_im[i, j, :].sum()
else:
# 更新已有标签
pixels_in_label = (labels == k)
weight_sum = (weight_im[i, j, :] * pixels_in_label).sum()
energy[k] = weight_sum - beta * num_diff_labels
# 分配标签
new_label = energy.argmin()
labels[i, j] = new_label
if new_label == num_labels:
num_labels += 1
# 更新标签直方图
label_hist.fill(0)
for i in range(h):
for j in range(w):
label_hist[labels[i, j]] += 1
# 压缩标签
labels_old = labels.copy()
for i in range(h):
for j in range(w):
if label_hist[labels[i, j]] < 10:
neighbor_labels = np.zeros(num_neighbors, dtype=int)
for k in range(num_neighbors):
if k == 0:
neighbor_labels[k] = labels[i-1, j] if i > 0 else -1
elif k == 1:
neighbor_labels[k] = labels[i, j-1] if j > 0 else -1
elif k == 2:
neighbor_labels[k] = labels[i-1, j-1] if i > 0 and j > 0 else -1
else:
neighbor_labels[k] = labels[i+1, j-1] if i < h-1 and j > 0 else -1
neighbor_labels = neighbor_labels[neighbor_labels >= 0]
label_counts = np.zeros(num_labels, dtype=int)
for k in range(len(neighbor_labels)):
label_counts[neighbor_labels[k]] += 1
new_label = label_counts.argmax()
labels[i, j] = new_label
# 如果标签没有发生变化,则提前结束迭代
if (labels_old == labels).all():
break
return labels
```
请注意,这只是一个示例实现,可能需要根据具体情况进行调整。
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