C++编写程序，找出一个5行5列的二维数组的靶点，即该位置上的元素在该行元素中最大

且在该列元素中最小。以下是C++程序的示例代码：

#include <iostream>
using namespace std;

int main() {
    int matrix[5][5] = {{1, 2, 3, 4, 5}, {6, 7, 8, 9, 10}, {11, 12, 13, 14, 15}, {16, 17, 18, 19, 20}, {21, 22, 23, 24, 25}};
    int rowMax, colMin, targetRow, targetCol;
    bool found = false;

    for (int i = 0; i < 5; i++) {
        rowMax = matrix[i][0];
        for (int j = 1; j < 5; j++) {
            if (matrix[i][j] > rowMax) {
                rowMax = matrix[i][j];
            }
        }
        for (int j = 0; j < 5; j++) {
            colMin = matrix[0][j];
            for (int k = 1; k < 5; k++) {
                if (matrix[k][j] < colMin) {
                    colMin = matrix[k][j];
                }
            }
            if (matrix[i][j] == rowMax && matrix[i][j] == colMin) {
                targetRow = i;
                targetCol = j;
                found = true;
                break;
            }
        }
        if (found) {
            break;
        }
    }

    if (found) {
        cout << "The target point is at (" << targetRow << "," << targetCol << ") and its value is " << matrix[targetRow][targetCol] << endl;
    } else {
        cout << "The target point is not found" << endl;
    }

    return 0;
}

在上述程序中，我们首先定义了一个5行5列的二维数组`matrix`，然后使用两个for循环分别找出每一行的最大值和每一列的最小值，同时在第二个for循环中判断当前元素是否为靶点。如果找到了靶点，我们就记录下它的行和列，并将`found`标记为`true`，然后跳出所有循环。最后，我们根据`found`的值来输出结果。