x=2.5,a=7,y=4.7,x+a%3*(int)(x+y)%2/4;
时间: 2024-05-22 09:16:58 浏览: 12
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相关问题
在c语言中,设x=2.5,a=7,y=4.7,表达式x+a%3*(int)(x+y)%2/4的结果是
在C语言中,% 表示取模运算符,其优先级高于加减乘除运算符。先按照运算符优先级进行计算,其计算过程如下:
1. a%3 = 1 (7除以3余1)
2. (int)(x+y) = (int)(2.5+4.7) = 7 (强制类型转换为整型)
3. (int)(x+y)%2 = 1 (7除以2余1)
4. 1/4 = 0 (整数除法)
5. 1*0 = 0
6. x+0 = 2.5
因此,表达式x+a%3*(int)(x+y)%2/4的结果为2.5。
设x=2.5,a=7,y=4.7,算术表达式x+a%3*(int)(x+y)%2/4的值为
根据运算符的优先级,首先要进行括号内的运算,int表示取整,因此(int)(x+y)的值为7。然后是%运算符,a%3的值为1。接着是/运算符,2/4的值为0。最后进行加法和乘法运算,得到的结果为:
2.5 + 1 * 0 = 2.5
因此,算术表达式x+a%3*(int)(x+y)%2/4的值为2.5。