使用pygame制作消消乐游戏

好的，下面是一个使用Pygame制作消消乐游戏的示例代码。这个示例代码包括了游戏的基本逻辑和界面设计，你可以在此基础上进行修改和扩展。

import pygame
import random

# 初始化Pygame
pygame.init()

# 设置窗口大小和标题
WINDOW_SIZE = (400, 500)
window = pygame.display.set_mode(WINDOW_SIZE)
pygame.display.set_caption("消消乐游戏")

# 定义游戏区域的大小和位置
BOARD_SIZE = (300, 300)
BOARD_LEFT = (WINDOW_SIZE[0] - BOARD_SIZE[0]) // 2
BOARD_TOP = 100

# 定义方块的大小和间隔
BLOCK_SIZE = 40
BLOCK_GAP = 5

# 定义方块的颜色
COLORS = [
    (255, 0, 0),
    (0, 255, 0),
    (0, 0, 255),
    (255, 255, 0),
    (255, 0, 255),
    (0, 255, 255),
]

# 定义游戏区域的矩形
board_rect = pygame.Rect(BOARD_LEFT, BOARD_TOP, BOARD_SIZE[0], BOARD_SIZE[1])

# 定义一个二维数组来存储方块的颜色
board = [[random.choice(COLORS) for j in range(BOARD_SIZE[0] // (BLOCK_SIZE + BLOCK_GAP))] for i in range(BOARD_SIZE[1] // (BLOCK_SIZE + BLOCK_GAP))]

# 定义一个函数来绘制方块
def draw_block(x, y, color):
    block_rect = pygame.Rect(BOARD_LEFT + x * (BLOCK_SIZE + BLOCK_GAP), BOARD_TOP + y * (BLOCK_SIZE + BLOCK_GAP), BLOCK_SIZE, BLOCK_SIZE)
    pygame.draw.rect(window, color, block_rect)

# 定义一个函数来检查是否有可以消除的方块
def check_matches():
    matches = []
    for i in range(len(board)):
        for j in range(len(board[i])):
            color = board[i][j]
            if color != None:
                if i < len(board) - 2 and board[i+1][j] == color and board[i+2][j] == color:
                    matches.append((j, i, 0))
                if j < len(board[i]) - 2 and board[i][j+1] == color and board[i][j+2] == color:
                    matches.append((j, i, 1))
    return matches

# 定义一个函数来消除方块
def remove_blocks(matches):
    for match in matches:
        x, y, direction = match
        if direction == 0:
            board[y][x] = None
            board[y+1][x] = None
            board[y+2][x] = None
        elif direction == 1:
            board[y][x] = None
            board[y][x+1] = None
            board[y][x+2] = None

# 游戏循环
running = True
while running:
    # 处理事件
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False
        elif event.type == pygame.MOUSEBUTTONDOWN:
            # 获取鼠标点击的位置
            x, y = event.pos
            # 如果鼠标点击在游戏区域内
            if board_rect.collidepoint(x, y):
                # 计算方块的索引
                block_x = (x - BOARD_LEFT) // (BLOCK_SIZE + BLOCK_GAP)
                block_y = (y - BOARD_TOP) // (BLOCK_SIZE + BLOCK_GAP)
                # 如果方块存在
                if board[block_y][block_x] != None:
                    # 将方块标记为None
                    board[block_y][block_x] = None
                    # 检查是否有可以消除的方块
                    matches = check_matches()
                    while len(matches) > 0:
                        # 消除方块
                        remove_blocks(matches)
                        # 将上方的方块掉落下来
                        for i in range(len(board)-1, 0, -1):
                            for j in range(len(board[i])):
                                if board[i][j] == None:
                                    board[i][j], board[i-1][j] = board[i-1][j], None
                        # 在上方生成新的方块
                        for j in range(len(board[0])):
                            if board[0][j] == None:
                                board[0][j] = random.choice(COLORS)
                        # 再次检查是否有可以消除的方块
                        matches = check_matches()

    # 绘制背景
    window.fill((255, 255, 255))

    # 绘制游戏区域的背景
    pygame.draw.rect(window, (200, 200, 200), board_rect)

    # 绘制方块
    for i in range(len(board)):
        for j in range(len(board[i])):
            if board[i][j] != None:
                draw_block(j, i, board[i][j])

    # 更新屏幕
    pygame.display.flip()

# 退出Pygame
pygame.quit()

在这个示例代码中，我们使用Pygame创建了一个名为"消消乐游戏"的窗口，并在窗口中绘制了一个游戏区域和方块。玩家可以通过点击方块来消除它们，如果有三个或以上颜色相同的方块相连，则它们将被消除。在消除方块后，上方的方块将掉落下来，同时在上方生成新的方块。我们还使用了随机函数来生成方块的颜色。