cpp的boost库怎么判断json值的类型
时间: 2024-05-12 14:19:44 浏览: 130
Boost库中有一个Json库,可以通过以下方式判断Json值的类型:
1. 使用value()方法获取Json值的类型枚举值,然后根据枚举值判断类型。
```cpp
#include <boost/json.hpp>
using namespace boost::json;
value jv = parse(R"({ "name":"John", "age":30, "city":"New York" })");
switch (jv.kind()) {
case kind::object:
std::cout << "object\n";
break;
case kind::array:
std::cout << "array\n";
break;
case kind::string:
std::cout << "string\n";
break;
case kind::int64:
std::cout << "integer\n";
break;
case kind::uint64:
std::cout << "unsigned integer\n";
break;
case kind::double_:
std::cout << "floating point number\n";
break;
case kind::bool_:
std::cout << "boolean value\n";
break;
case kind::null:
std::cout << "null value\n";
break;
}
```
2. 使用is_xxx()方法判断Json值的类型。
```cpp
#include <boost/json.hpp>
using namespace boost::json;
value jv = parse(R"({ "name":"John", "age":30, "city":"New York" })");
if (jv.is_object()) {
std::cout << "object\n";
} else if (jv.is_array()) {
std::cout << "array\n";
} else if (jv.is_string()) {
std::cout << "string\n";
} else if (jv.is_int64()) {
std::cout << "integer\n";
} else if (jv.is_uint64()) {
std::cout << "unsigned integer\n";
} else if (jv.is_double()) {
std::cout << "floating point number\n";
} else if (jv.is_bool()) {
std::cout << "boolean value\n";
} else if (jv.is_null()) {
std::cout << "null value\n";
}
```
以上两种方法都可以判断Json值的类型,根据实际情况选择使用。
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