for i, rect in enumerate(sorted(rects, key=lambda x: x[1][0] * x[1][1], reverse=True)): box = cv2.boxPoints(rect) box = np.int0(box) print( f'Rank {i + 1}: Size={rect[1][0] * rect[1][1]:.0f}, Centre=({int(rect[0][0])}, {int(rect[0][1])}), Width={rect[1][0]:.0f}, Height={rect[1][1]:.0f}, Angle={rect[2]:.0f}, \nCorners={box}')改为只打印排名前三的

可以在循环中添加一个计数器变量，用来记录已经打印的矩形数量，当数量达到3时退出循环即可。修改后的代码如下：

count = 0
for i, rect in enumerate(sorted(rects, key=lambda x: x[1][0] * x[1][1], reverse=True)):
    if count >= 3:
        break
    box = cv2.boxPoints(rect)
    box = np.int0(box)
    print(f'Rank {i + 1}: Size={rect[1][0] * rect[1][1]:.0f}, Centre=({int(rect[0][0])}, {int(rect[0][1])}), Width={rect[1][0]:.0f}, Height={rect[1][1]:.0f}, Angle={rect[2]:.0f}, \nCorners={box}')
    count += 1

这样就只会打印排名前三的矩形信息了。