使用循环输出九九乘法表

好的，这是使用Python语言输出九九乘法表的代码：

for i in range(1, 10):
    for j in range(1, i+1):
        print('{}x{}={}\t'.format(j, i, i*j), end='')
    print()

运行结果如下：

1x1=1    
1x2=2    2x2=4    
1x3=3    2x3=6    3x3=9    
1x4=4    2x4=8    3x4=12   4x4=16   
1x5=5    2x5=10   3x5=15   4x5=20   5x5=25   
1x6=6    2x6=12   3x6=18   4x6=24   5x6=30   6x6=36   
1x7=7    2x7=14   3x7=21   4x7=28   5x7=35   6x7=42   7x7=49   
1x8=8    2x8=16   3x8=24   4x8=32   5x8=40   6x8=48   7x8=56   8x8=64   
1x9=9    2x9=18   3x9=27   4x9=36   5x9=45   6x9=54   7x9=63   8x9=72   9x9=81   

希望能帮到你！

相关问题

输出九九乘法表 编写一个程序，使用嵌套循环输出九九乘法表用c语言

以下是使用嵌套循环输出九九乘法表的C语言程序：

#include <stdio.h>

int main() {
    int i, j;
    for (i = 1; i <= 9; i++) {
        for (j = 1; j <= i; j++) {
            printf("%d*%d=%-2d ", j, i, i * j);
        }
        printf("\n");
    }
    return 0;
}

该程序使用两个嵌套的循环，外循环控制行数（1到9），内循环控制每一行中的乘法表达式。程序将每一行的结果打印出来，确保每个数字都占用两个字符的宽度，以保持格式整齐。

使用双重循环输出九九乘法表

Sure, here's the code to output the multiplication table for numbers 1 to 9:

for i in range(1, 10):
    for j in range(1, i+1):
        print(f"{i} x {j} = {i*j}", end="\t")
    print()

This will give you the table in the format:

1 x 1 = 1	
2 x 1 = 2	2 x 2 = 4	
3 x 1 = 3	3 x 2 = 6	3 x 3 = 9	
4 x 1 = 4	4 x 2 = 8	4 x 3 = 12	4 x 4 = 16	
5 x 1 = 5	5 x 2 = 10	5 x 3 = 15	5 x 4 = 20	5 x 5 = 25	
6 x 1 = 6	6 x 2 = 12	6 x 3 = 18	6 x 4 = 24	6 x 5 = 30	6 x 6 = 36	
7 x 1 = 7	7 x 2 = 14	7 x 3 = 21	7 x 4 = 28	7 x 5 = 35	7 x 6 = 42	7 x 7 = 49	
8 x 1 = 8	8 x 2 = 16	8 x 3 = 24	8 x 4 = 32	8 x 5 = 40	8 x 6 = 48	8 x 7 = 56	8 x 8 = 64	
9 x 1 = 9	9 x 2 = 18	9 x 3 = 27	9 x 4 = 36	9 x 5 = 45	9 x 6 = 54	9 x 7 = 63	9 x 8 = 72	9 x 9 = 81