请用python写一个贪吃蛇
时间: 2023-10-15 07:04:34 浏览: 66
好的,这里是一个简单的贪吃蛇实现,使用Python和Pygame库:
```python
import pygame
import random
# 初始化Pygame
pygame.init()
# 游戏窗口大小
win_width = 500
win_height = 500
# 初始化游戏窗口
win = pygame.display.set_mode((win_width, win_height))
pygame.display.set_caption("贪吃蛇")
# 定义颜色
white = (255, 255, 255)
black = (0, 0, 0)
red = (255, 0, 0)
# 定义贪吃蛇
snake_block_size = 10
snake_speed = 15
# 定义字体
font_style = pygame.font.SysFont(None, 30)
def message(msg, color):
msg_render = font_style.render(msg, True, color)
win.blit(msg_render, [win_width / 6, win_height / 3])
def game_loop():
# 初始位置
x1 = win_width / 2
y1 = win_height / 2
# x1, y1 是贪吃蛇的头部
x1_change = 0
y1_change = 0
# 食物的位置
foodx = round(random.randrange(0, win_width - snake_block_size) / 10.0) * 10.0
foody = round(random.randrange(0, win_height - snake_block_size) / 10.0) * 10.0
game_over = False
while not game_over:
for event in pygame.event.get():
if event.type == pygame.QUIT:
game_over = True
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
x1_change = -snake_block_size
y1_change = 0
elif event.key == pygame.K_RIGHT:
x1_change = snake_block_size
y1_change = 0
elif event.key == pygame.K_UP:
y1_change = -snake_block_size
x1_change = 0
elif event.key == pygame.K_DOWN:
y1_change = snake_block_size
x1_change = 0
# 判断贪吃蛇是否撞墙
if x1 >= win_width or x1 < 0 or y1 >= win_height or y1 < 0:
game_over = True
# 移动贪吃蛇
x1 += x1_change
y1 += y1_change
# 绘制背景
win.fill(white)
# 绘制食物
pygame.draw.rect(win, red, [foodx, foody, snake_block_size, snake_block_size])
# 绘制贪吃蛇
pygame.draw.rect(win, black, [x1, y1, snake_block_size, snake_block_size])
# 更新窗口
pygame.display.update()
# 判断是否吃到食物
if x1 == foodx and y1 == foody:
print("Yummy!!")
# 游戏帧率
clock = pygame.time.Clock()
clock.tick(snake_speed)
# 退出Pygame
pygame.quit()
quit()
# 开始游戏循环
game_loop()
```
这只是一个简单的实现,还有很多可以改进的地方,比如增加贪吃蛇的长度、增加难度等等。