python 实现贪食蛇游戏 源代码

可以这样写：

import curses
from random import randint

# 初始化屏幕和颜色
curses.initscr()
curses.start_color()
curses.init_pair(1, curses.COLOR_GREEN, curses.COLOR_BLACK)
win = curses.newwin(20, 60, 0, 0)
win.keypad(1)
win.border(0)
win.nodelay(1)

# 初始化蛇和食物
snake = [(4, 10), (4, 9), (4, 8)]
food = (10, 20)

# 初始化分数
score = 0

# 绘制蛇和食物的函数
def draw_snake(snake):
    for y, x in snake:
        win.addch(y, x, '*', curses.color_pair(1))
    win.addch(food[0], food[1], '#')

# 移动蛇的函数
def move_snake(key, snake):
    head = snake[0]
    if key == curses.KEY_DOWN:
        new_head = (head[0] + 1, head[1])
    elif key == curses.KEY_UP:
        new_head = (head[0] - 1, head[1])
    elif key == curses.KEY_LEFT:
        new_head = (head[0], head[1] - 1)
    elif key == curses.KEY_RIGHT:
        new_head = (head[0], head[1] + 1)
    else:
        new_head = head
    snake.insert(0, new_head)

    # 如果吃到了食物，更新食物和分数
    if snake[0] == food:
        food = None
        score += 1
        while food is None:
            nf = (randint(1, 18), randint(1, 58))
            food = nf if nf not in snake else None
        win.addch(food[0], food[1], '#')
    else:
        tail = snake.pop()
        win.addch(tail[0], tail[1], ' ')
    return score

# 游戏主循环
while True:
    # 获取键盘输入
    key = win.getch()
    if key == 27: # 如果按了Esc键，退出游戏
        break
    score = move_snake(key, snake)
    win.border(0)
    win.addstr(0, 2, 'Score : ' + str(score) + ' ')
    win.refresh()

# 清理屏幕和结束游戏
curses.endwin()
print("Final Score : " + str(score))