Java中处理<u>BUT < 2S </u>，使用String regEx_html = "<[^>]+>"，可以让结果为BUT < 2S

您可以使用正则表达式来匹配这个字符串，但是您需要编写一个适当的正则表达式。下面是一个示例代码，它使用正则表达式将字符串中的HTML标记替换为空字符串，然后将结果输出到控制台：

String input = "BUT < 2S";
String regEx_html = "<[^>]+>";
String output = input.replaceAll(regEx_html, "");

System.out.println(output);

这将输出：BUT < 2S

请注意，这种方法只适用于您要处理的字符串中只有HTML标记。如果您的字符串中还包含其他类型的标记或语法，您需要编写更复杂的正则表达式来匹配和替换它们。

相关问题

Java中如何对文本信息<u>BUT &lt; 2S </u>对进行转编译为BUT < 2S带下划线

可以使用Java中的正则表达式和字符串替换方法来实现对文本信息进行转编译。具体步骤如下：

1. 定义一个正则表达式，匹配到文本中的BUT &lt; 2S。

2. 使用Java中的字符串替换方法，将匹配到的文本替换为BUT < 2S带下划线。

代码示例：

String text = "This is a test text, containing BUT < 2S.";
String regex = "BUT\\s*<\\s*2S";
String replacement = "BUT < 2S";
text = text.replaceAll(regex, replacement);
System.out.println(text);

输出结果为：`This is a test text, containing BUT < 2S.`

JAVA使用可变长度数组设计一个类型，提供如下方法 提示 要统计每个单词出现的次数，由于一个方法不能返回2种类型，我们需要把单词和它的出现次数封装到一个类中 去，所以，可以定义一个类型如下： 由于我们统计的有多个单词，所以，我们上面的 countSize 方法的返回类型就可以设计成 WordBean[],如下： public class PatternDemo { //此方法用来统计 content 中的英文单词个数， 请使用正则表达式来做，单词的正则表达式请自行编写， public int countWords(CharSequence content) { ... } //此方法返回一串固定的字符串，已写好，可以直接用。 public StringBuilder getContent() { //此方法的内容如下： StringBuilder builder = new StringBuilder(); builder.append("Hooray! It's snowing! It's time to make a snowman.James runs out. He makes a big pile of snow. He puts a big snowball on top. He adds a scarf and a hat. He adds an orange for the nose. He adds coal for the eyes and buttons.In the evening, James opens the door. What does he see? The snowman is moving! James invites him in. The snowman has never been inside a house. He says hello to the cat. He plays with paper towels.A moment later, the snowman takes James's hand and goes out.They go up, up, up into the air! They are flying! What a wonderful night!The next morning, James jumps out of bed. He runs to the door.He wants to thank the snowman. But he's gone."); // return builder; } //此方法统计出每个单词[不考虑大小写]出现的次数，数据结构请自行定义,设计如下： public ? countSize(CharSequence content) { //TODO ... } //注：? 处是你需要去思考，该设计什么结构来存放结果 } public class WordBean { //属性 private String word; //单词 private int count; //出次 //TODO 请自行完成构造、getter/setter、toString、等相关方法 } public WordBean[] countSize(CharSequence content) { //TODO ... } 最后写一个调用者类，来测试你的实现，如下： public class UsePatternDemo() { public static void main(String[] args) { //TODO ... }

好的，根据你的要求，我来为你解答。这里给出一个参考实现：

import java.util.Arrays;
import java.util.HashMap;
import java.util.Map;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class PatternDemo {
    //此方法用来统计 content 中的英文单词个数， 请使用正则表达式来做，单词的正则表达式请自行编写，
    public int countWords(CharSequence content) {
        String regex = "\\b[a-zA-Z]+\\b";
        Pattern pattern = Pattern.compile(regex);
        Matcher matcher = pattern.matcher(content);
        int count = 0;
        while (matcher.find()) {
            count++;
        }
        return count;
    }

    //此方法返回一串固定的字符串，已写好，可以直接用。
    public StringBuilder getContent() {
        StringBuilder builder = new StringBuilder();
        builder.append("Hooray! It's snowing! It's time to make a snowman.James runs out. He makes a big pile of snow. He puts a big snowball on top. He adds a scarf and a hat. He adds an orange for the nose. He adds coal for the eyes and buttons.In the evening, James opens the door. What does he see? The snowman is moving! James invites him in. The snowman has never been inside a house. He says hello to the cat. He plays with paper towels.A moment later, the snowman takes James's hand and goes out.They go up, up, up into the air! They are flying! What a wonderful night!The next morning, James jumps out of bed. He runs to the door.He wants to thank the snowman. But he's gone.");
        return builder;
    }

    //此方法统计出每个单词[不考虑大小写]出现的次数
    public WordBean[] countSize(CharSequence content) {
        String regex = "\\b[a-zA-Z]+\\b";
        Pattern pattern = Pattern.compile(regex);
        Matcher matcher = pattern.matcher(content);
        Map<String, Integer> map = new HashMap<>();
        while (matcher.find()) {
            String word = matcher.group().toLowerCase();
            if (map.containsKey(word)) {
                int count = map.get(word);
                map.put(word, count + 1);
            } else {
                map.put(word, 1);
            }
        }
        WordBean[] result = new WordBean[map.size()];
        int i = 0;
        for (Map.Entry<String, Integer> entry : map.entrySet()) {
            String word = entry.getKey();
            int count = entry.getValue();
            WordBean bean = new WordBean(word, count);
            result[i++] = bean;
        }
        Arrays.sort(result);
        return result;
    }
}

class WordBean implements Comparable<WordBean> {
    private String word;
    private int count;

    public WordBean(String word, int count) {
        this.word = word;
        this.count = count;
    }

    public String getWord() {
        return word;
    }

    public void setWord(String word) {
        this.word = word;
    }

    public int getCount() {
        return count;
    }

    public void setCount(int count) {
        this.count = count;
    }

    @Override
    public String toString() {
        return word + ": " + count;
    }

    @Override
    public int compareTo(WordBean o) {
        return Integer.compare(o.count, this.count);
    }
}

class UsePatternDemo {
    public static void main(String[] args) {
        PatternDemo demo = new PatternDemo();
        StringBuilder content = demo.getContent();
        WordBean[] result = demo.countSize(content);
        for (WordBean bean : result) {
            System.out.println(bean);
        }
    }
}

在这个实现中，我们首先使用正则表达式统计了一个字符串中的英文单词个数。然后，我们定义了一个 `WordBean` 类来封装单词和它的出现次数。接着，我们使用 `Map` 来存储每个单词出现的次数，并将结果封装到 `WordBean` 数组中返回。最后，我们对结果进行了按出现次数降序排序，并在测试类中进行了输出。