int* operator[](int nIndex) { } 返回值怎么写
时间: 2024-03-13 22:47:07 浏览: 68
这个函数是一个运算符重载函数,它重载了下标运算符[],返回类型应该是一个指向整型的指针(int*)。所以函数声明应该是这样的:
```c++
int* operator[](int nIndex) { }
```
需要注意的是,这个函数并没有实现具体的功能,需要根据具体的应用场景来实现相应的功能。
相关问题
*(int*)a-*(int*)b
This is a C expression for subtracting two integers.
- `a` and `b` are pointers to memory locations where integers are stored.
- `(int*)a` and `(int*)b` cast the pointers to type `int*`, indicating that the memory locations should be treated as integers.
- `*(int*)a` and `*(int*)b` dereference the pointers to retrieve the integer values stored in those memory locations.
- The two integers are then subtracted using the `-` operator.
Overall, the expression computes the difference between the integer values stored at memory locations pointed to by `a` and `b`.
int *a=new int[50]
This line of code creates a dynamic array of 50 integers and assigns a pointer to the first element of the array to the variable 'a'. The 'new' operator is used to allocate memory for the array on the heap, and the 'int' keyword specifies the data type of the elements in the array.
Since this is a dynamic array, the size of the array can be changed at runtime by using the 'delete' operator to deallocate the current array and then creating a new array with a different size using the 'new' operator. It is important to remember to deallocate the memory allocated by the 'new' operator using the 'delete' operator when the array is no longer needed to avoid memory leaks.