帮我写一篇四位数码管从1到9999的代码
时间: 2024-03-22 21:42:54 浏览: 22
好的,以下是一种基于Arduino的实现方式:
```c
int digitPins[] = {2, 3, 4, 5}; // 数码管的4个数字引脚
int segPins[] = {6, 7, 8, 9, 10, 11, 12}; // 数码管的7个段引脚
int num[4]; // 存储当前要显示的数字
void setup() {
// 初始化引脚
for (int i = 0; i < 4; i++) {
pinMode(digitPins[i], OUTPUT);
}
for (int i = 0; i < 7; i++) {
pinMode(segPins[i], OUTPUT);
}
}
void loop() {
for (int i = 1; i < 10000; i++) {
// 将当前数字的每一位存储到数组中
num[0] = i % 10;
num[1] = (i / 10) % 10;
num[2] = (i / 100) % 10;
num[3] = (i / 1000) % 10;
// 显示数字
for (int j = 0; j < 4; j++) {
displayDigit(num[j], digitPins[j], segPins);
}
// 等待一段时间,显示下一个数字
delay(1000);
}
}
void displayDigit(int digit, int digitPin, int segPins[]) {
// 根据要显示的数字确定哪些段需要点亮
boolean segs[] = {LOW, LOW, LOW, LOW, LOW, LOW, LOW}; // 7个段的状态,LOW表示关闭
switch (digit) {
case 0:
segs[0] = HIGH;
segs[1] = HIGH;
segs[2] = HIGH;
segs[3] = HIGH;
segs[4] = HIGH;
segs[5] = HIGH;
break;
case 1:
segs[1] = HIGH;
segs[2] = HIGH;
break;
case 2:
segs[0] = HIGH;
segs[1] = HIGH;
segs[6] = HIGH;
segs[4] = HIGH;
segs[3] = HIGH;
break;
case 3:
segs[0] = HIGH;
segs[1] = HIGH;
segs[6] = HIGH;
segs[2] = HIGH;
segs[3] = HIGH;
break;
case 4:
segs[5] = HIGH;
segs[6] = HIGH;
segs[1] = HIGH;
segs[2] = HIGH;
break;
case 5:
segs[0] = HIGH;
segs[5] = HIGH;
segs[6] = HIGH;
segs[2] = HIGH;
segs[3] = HIGH;
break;
case 6:
segs[0] = HIGH;
segs[5] = HIGH;
segs[6] = HIGH;
segs[2] = HIGH;
segs[3] = HIGH;
segs[4] = HIGH;
break;
case 7:
segs[0] = HIGH;
segs[1] = HIGH;
segs[2] = HIGH;
break;
case 8:
segs[0] = HIGH;
segs[1] = HIGH;
segs[2] = HIGH;
segs[3] = HIGH;
segs[4] = HIGH;
segs[5] = HIGH;
segs[6] = HIGH;
break;
case 9:
segs[0] = HIGH;
segs[1] = HIGH;
segs[2] = HIGH;
segs[3] = HIGH;
segs[5] = HIGH;
segs[6] = HIGH;
break;
}
// 逐个点亮需要点亮的段
for (int i = 0; i < 7; i++) {
digitalWrite(segPins[i], segs[i]);
}
// 选中当前要显示的数字
digitalWrite(digitPin, LOW);
// 等待一段时间后关闭数码管
delay(5);
digitalWrite(digitPin, HIGH);
// 关闭所有段
for (int i = 0; i < 7; i++) {
digitalWrite(segPins[i], LOW);
}
}
```
注:此代码可能需要根据具体硬件进行适当的修改。
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