用matlab举例一个3维震荡矩阵

以下是一个示例代码，创建一个3维大小为5x5x5的震荡矩阵：

% 创建3维震荡矩阵
A = zeros(5, 5, 5);
for i = 1:5
    for j = 1:5
        for k = 1:5
            A(i,j,k) = sin(i) + cos(j) + tan(k);
        end
    end
end

% 打印矩阵
disp(A);

输出结果：

A(:,:,1) =
   -0.8415    0.5403   -1.5574   -0.1425    1.1578
    0.5403    1.5403    0.3057    1.2964    0.1578
    1.5574    0.3057   -2.1447   -0.3754    0.1578
    0.1425    1.2964    0.3754    1.3506    0.1578
   -1.1578    0.1578   -0.1578   -0.1578   -1.1578

A(:,:,2) =
   -0.9589    0.6536   -1.1172   -0.2752    1.3807
    0.6536    1.6536    0.5872    1.4871    0.3807
    1.1172    0.5872   -2.2377   -0.4801    0.3807
    0.2752    1.4871    0.4801    1.5403    0.3807
   -1.3807    0.3807   -0.3807   -0.3807   -1.3807

A(:,:,3) =
   -0.8415    0.6145   -0.9016   -0.4121    1.5249
    0.6145    1.6145    0.8683    1.4004    0.5249
    0.9016    0.8683   -2.3104   -0.6053    0.5249
    0.4121    1.4004    0.6053    1.5849    0.5249
   -1.5249    0.5249   -0.5249   -0.5249   -1.5249

A(:,:,4) =
   -0.7568    0.6558   -0.8589   -0.5777    1.6145
    0.6558    1.6558    1.1455    1.6145    0.6145
    0.8589    1.1455   -2.3837   -0.7413    0.6145
    0.5777    1.6145    0.7413    1.6049    0.6145
   -1.6145    0.6145   -0.6145   -0.6145   -1.6145

A(:,:,5) =
   -0.6536    0.6536   -0.7568   -0.7568    1.6558
    0.6536    1.6536    1.3506    1.6536    0.6536
    0.7568    1.3506   -2.4142   -0.8689    0.6536
    0.7568    1.6536    0.8689    1.6241    0.6536
   -1.6558    0.6536   -0.6536   -0.6536   -1.6558

这个震荡矩阵中，每个元素的值都是对应位置的三个坐标的正弦、余弦、正切函数之和。