pycharm实现五子棋代码

在PyCharm中实现五子棋的代码，通常涉及几个关键部分：棋盘的显示、玩家输入、胜负判断和游戏循环。以下是一个简化版的五子棋实现，使用Python编写：

# 定义棋盘大小
BOARD_SIZE = 15

# 初始化棋盘
def init_board():
    return [["." for _ in range(BOARD_SIZE)] for _ in range(BOARD_SIZE)]

# 打印棋盘
def print_board(board):
    for row in board:
        print(" ".join(row))

# 检查是否有玩家获胜
def check_win(board, row, col, player):
    directions = [(0, 1), (1, 0), (1, 1), (1, -1)]  # 水平、垂直、两个对角线方向
    for d in directions:
        count = 1  # 连续棋子的计数器
        # 检查正方向
        for i in range(1, 5):
            r = row + i * d[0]
            c = col + i * d[1]
            if 0 <= r < BOARD_SIZE and 0 <= c < BOARD_SIZE and board[r][c] == player:
                count += 1
            else:
                break
        # 检查反方向
        for i in range(1, 5):
            r = row - i * d[0]
            c = col - i * d[1]
            if 0 <= r < BOARD_SIZE and 0 <= c < BOARD_SIZE and board[r][c] == player:
                count += 1
            else:
                break
        # 检查是否有5个连续的棋子
        if count >= 5:
            return True
    return False

# 主游戏循环
def main():
    board = init_board()
    turn = "X"  # X玩家先手
    while True:
        print_board(board)
        try:
            row, col = map(int, input(f"Player {turn}, enter your move (row col): ").split())
        except ValueError:
            print("Invalid input. Please enter numbers separated by space.")
            continue
        if not (0 <= row < BOARD_SIZE and 0 <= col < BOARD_SIZE):
            print("Invalid move. Please try again.")
            continue
        if board[row][col] != ".":
            print("This cell is already taken. Please try again.")
            continue
        board[row][col] = turn
        if check_win(board, row, col, turn):
            print_board(board)
            print(f"Player {turn} wins!")
            break
        turn = "O" if turn == "X" else "X"  # 切换玩家

if __name__ == "__main__":
    main()

这段代码实现了基本的五子棋游戏逻辑，包括初始化棋盘、打印棋盘、玩家输入、胜负判断和游戏循环。玩家交替输入坐标来放置棋子，当一方玩家在横、竖、斜任一方向上连成五个棋子时，游戏结束，该玩家获胜。