定义数组arr,值为[‘a’, ‘b’, ‘b’, ‘c’, ‘d’, ’d’],统计重复的字符有多少个,几种方法,j
时间: 2023-09-26 10:08:04 浏览: 30
有以下几种方法统计重复的字符个数:
1. 使用循环和计数器统计重复字符个数
```python
arr = ['a', 'b', 'b', 'c', 'd', 'd']
count = 0
for i in range(len(arr)):
for j in range(i+1, len(arr)):
if arr[i] == arr[j]:
count += 1
print("重复字符个数为:", count)
```
2. 使用集合去重,计算重复字符个数
```python
arr = ['a', 'b', 'b', 'c', 'd', 'd']
count = len(arr) - len(set(arr))
print("重复字符个数为:", count)
```
3. 使用Counter计算每个字符出现的次数,统计重复字符个数
```python
from collections import Counter
arr = ['a', 'b', 'b', 'c', 'd', 'd']
count = 0
counter = Counter(arr)
for c in counter:
if counter[c] > 1:
count += 1
print("重复字符个数为:", count)
```
相关问题
定义数组arr,值为[‘a’, ‘b’, ‘b’, ‘c’, ‘d’, ’d’],统计重复的字符有多少个,几种方法
有以下几种方法可以统计重复的字符数量:
1. 使用Counter类
```python
from collections import Counter
arr = ['a', 'b', 'b', 'c', 'd', 'd']
counter = Counter(arr)
# 统计重复的字符数量
duplicate_count = sum([count - 1 for count in counter.values() if count > 1])
print(duplicate_count) # 3
# 统计重复的字符种类数量
duplicate_type_count = len([count for count in counter.values() if count > 1])
print(duplicate_type_count) # 2
```
2. 使用set和count方法
```python
arr = ['a', 'b', 'b', 'c', 'd', 'd']
duplicate_count = sum([arr.count(x) - 1 for x in set(arr) if arr.count(x) > 1])
print(duplicate_count) # 3
duplicate_type_count = len([x for x in set(arr) if arr.count(x) > 1])
print(duplicate_type_count) # 2
```
3. 使用for循环和字典
```python
arr = ['a', 'b', 'b', 'c', 'd', 'd']
count_dict = {}
# 统计每个字符出现的次数
for char in arr:
if char not in count_dict:
count_dict[char] = 0
count_dict[char] += 1
# 统计重复的字符数量
duplicate_count = sum([count - 1 for count in count_dict.values() if count > 1])
print(duplicate_count) # 3
# 统计重复的字符种类数量
duplicate_type_count = len([count for count in count_dict.values() if count > 1])
print(duplicate_type_count) # 2
```
请定义一个长度为4的数组,其值为( a , b , c , d ),输出所有元素。
好的,以下是定义数组并输出所有元素的代码(假设使用 Python 语言):
```python
arr = ['a', 'b', 'c', 'd']
for i in range(len(arr)):
print(arr[i])
```
输出结果为:
```
a
b
c
d
```