用java写一个 安排10个人上3天班，且一天要上4次休息2次为一个周期

以下是一个可能的 Java 代码实现：

import java.util.ArrayList;
import java.util.List;
import java.util.Random;

public class Schedule {
    private static final int NUM_PEOPLE = 10;
    private static final int NUM_DAYS = 3;
    private static final int NUM_SHIFTS_PER_DAY = 4;
    private static final int NUM_RESTS_PER_DAY = 2;
    private static final int NUM_PERIODS_PER_DAY = NUM_SHIFTS_PER_DAY + NUM_RESTS_PER_DAY;
    private static final int NUM_PERIODS = NUM_DAYS * NUM_PERIODS_PER_DAY;

    public static void main(String[] args) {
        List<Integer> schedule = generateSchedule();
        printSchedule(schedule);
    }

    private static List<Integer> generateSchedule() {
        List<Integer> schedule = new ArrayList<>(NUM_PERIODS);
        Random random = new Random();
        for (int i = 0; i < NUM_PERIODS; i++) {
            schedule.add(-1);
        }
        for (int person = 0; person < NUM_PEOPLE; person++) {
            for (int shift = 0; shift < NUM_SHIFTS_PER_DAY; shift++) {
                int period;
                do {
                    period = random.nextInt(NUM_PERIODS);
                } while (schedule.get(period) != -1);
                schedule.set(period, person);
            }
        }
        return schedule;
    }

    private static void printSchedule(List<Integer> schedule) {
        for (int day = 0; day < NUM_DAYS; day++) {
            System.out.println("Day " + (day + 1) + ":");
            for (int period = 0; period < NUM_PERIODS_PER_DAY; period++) {
                int person = schedule.get(day * NUM_PERIODS_PER_DAY + period);
                System.out.print("Period " + (period + 1) + ": ");
                if (person == -1) {
                    System.out.println("Rest");
                } else {
                    System.out.println("Person " + (person + 1));
                }
            }
        }
    }
}

这个程序使用了一个简单的随机算法来生成排班表。首先，它创建了一个长度为 `NUM_PERIODS` 的列表，每个元素代表一个时间段。然后，它循环遍历每个人和每个班次，为每个班次随机分配一个时间段，直到找到一个空闲的时间段为止。最后，它打印出生成的排班表。