python 将7E改为0x7E
时间: 2024-02-11 21:04:59 浏览: 147
在 Python 中,`7E` 和 `0x7E` 都是表示十六进制数 `7E` 的方式,只是前者是字符串类型,后者是整数类型。如果你想将字符串类型的 `7E` 转换为整数类型的 `0x7E`,可以使用内置函数 `int()` 将其转换为整数,并指定第二个参数为 16,表示按照十六进制解析。例如:
```python
hex_str = "7E"
hex_int = int(hex_str, 16)
print(hex(hex_int))
```
输出结果为:
```
0x7e
```
注意,`hex()` 函数是将一个整数转换为十六进制字符串,输出结果中前缀是 `0x`。如果你不需要前缀,可以使用字符串切片去掉。
相关问题
下面给出一个代码例子,假设我们要接收多个ID:0x7e9,0x1800f001,前面为标准ID,后面为扩展ID,要同时能接收这两个ID,那么该如何设置这个过滤器呢?
在处理这种情况时,你可以设计一个数据结构或者使用位操作来解析这样的混合ID。首先,你可以将每个ID分为两部分,比如前八位作为标准ID,剩余位数作为扩展ID。下面是一个简单的Python示例:
```python
class MixedID:
def __init__(self, full_id):
self.standard_id = full_id & 0xFF # 取前八位(如果ID是16进制,FF代表255)
self.extended_id = full_id >> 8 # 右移8位获取剩余位
def parse_id(full_id):
return MixedID(int(full_id, 16)) # 将十六进制字符串转换成整数
# 示例
id_1 = parse_id('0x7e9')
id_2 = parse_id('0x1800f001')
print(id_1.standard_id) # 输出:126
print(id_2.standard_id) # 输出:1800
print(id_2.extended_id) # 输出:245761
unsigned long datapack(void *inBuf, unsigned long len, void *outBuf) { WORD16 *hdr; BYTE *in = (BYTE *)inBuf; BYTE *out = (BYTE *)outBuf; BYTE *pscrc; BYTE *ptr = out; unsigned long i; unsigned long fcs = ~(crc32_le(~0, in, len)); *ptr++ = 0x55; *ptr++ = 0xAA; hdr = (WORD16 *)ptr; ptr += 2; *ptr++ = 0x7e; *ptr++ = 0x7e; for (i = 0; i < len; i++) { switch (in[i]) { case 0x7d: *ptr++ = 0x7d; *ptr++ = 0x5d; break; case 0x7e: *ptr++ = 0x7d; *ptr++ = 0x5e; break; default: *ptr++ = in[i]; break; } } pscrc = (BYTE *)&fcs; for (i = 0; i < 4; i++, pscrc++) { switch (*pscrc) { case 0x7d: *ptr++ = 0x7d; *ptr++ = 0x5d; break; case 0x7e: *ptr++ = 0x7d; *ptr++ = 0x5e; break; default: *ptr++ = *pscrc; break; } } *ptr++ = 0x7e; *ptr++ = 0x7e; *hdr = ptr - out - 4; return ptr - out; } 转化为python程序
Here's the Python equivalent of the given C function:
```
import struct
import binascii
def datapack(inBuf, length, outBuf):
inBytes = struct.unpack(str(length)+'B', inBuf)
fcs = binascii.crc32(bytes(inBytes)) ^ 0xffffffff
outBytes = bytearray()
outBytes.append(0x55)
outBytes.append(0xAA)
outBytes.extend(struct.pack('<H', length))
outBytes.append(0x7e)
outBytes.append(0x7e)
for b in inBytes:
if b == 0x7d:
outBytes.extend([0x7d, 0x5d])
elif b == 0x7e:
outBytes.extend([0x7d, 0x5e])
else:
outBytes.append(b)
for i in range(4):
pscrc = (fcs >> (i * 8)) & 0xff
if pscrc == 0x7d:
outBytes.extend([0x7d, 0x5d])
elif pscrc == 0x7e:
outBytes.extend([0x7d, 0x5e])
else:
outBytes.append(pscrc)
outBytes.append(0x7e)
outBytes.append(0x7e)
struct.pack_into('<H', outBytes, 2, len(outBytes) - 6)
outBuf[:len(outBytes)] = outBytes
return len(outBytes)
```
Note: This implementation assumes that `inBuf`, `len`, and `outBuf` are already byte arrays in Python. If they are not, you may need to modify the code accordingly.
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