matlab绘制风速风向玫瑰图

以下是一个绘制风速风向玫瑰图的示例MATLAB代码：

% 生成随机风速和风向数据
wind_speed = randi([0, 20], [1, 1000]);
wind_direction = randi([0, 360], [1, 1000]);

% 将风向数据转换为弧度制
theta = deg2rad(wind_direction);

% 将风向数据分为8个方向
num_directions = 8;
direction_bins = linspace(-pi, pi, num_directions + 1);

% 计算每个方向的风速平均值
speed_by_direction = zeros(1, num_directions);
for i = 1:num_directions
    indices = find((theta >= direction_bins(i)) & (theta < direction_bins(i+1)));
    speed_by_direction(i) = mean(wind_speed(indices));
end

% 绘制玫瑰图
figure;
polarplot(direction_bins, [speed_by_direction, speed_by_direction(1)], '-o');
thetaticks(rad2deg(direction_bins));
thetaticklabels({'N', 'NE', 'E', 'SE', 'S', 'SW', 'W', 'NW'});
rticks([0 5 10 15 20]);
title('Wind Rose Diagram');

该代码将生成1000个随机的风速和风向数据，将风向数据分为8个方向，并计算每个方向的风速平均值。最后，它将绘制一个玫瑰图，显示每个方向的平均风速。