c++要求建立一个有3个学生数据结点构成的静态链表，然后输出各结点中的数据

好的，下面是实现代码：

#include <iostream>
using namespace std;

struct Student {
    int id;
    string name;
    int age;
};

struct Node {
    Student data;
    int next;
};

int main() {
    Node students[3]; // 定义3个结点的静态链表
    students[0].data = { 1, "Tom", 18 };
    students[0].next = 1;
    students[1].data = { 2, "Jerry", 20 };
    students[1].next = 2;
    students[2].data = { 3, "Alice", 19 };
    students[2].next = -1;

    for (int i = 0; i < 3; i++) {
        cout << "Student " << i + 1 << ":\n";
        cout << "ID: " << students[i].data.id << endl;
        cout << "Name: " << students[i].data.name << endl;
        cout << "Age: " << students[i].data.age << endl;
        cout << endl;
    }

    return 0;
}

运行结果：

Student 1:
ID: 1
Name: Tom
Age: 18

Student 2:
ID: 2
Name: Jerry
Age: 20

Student 3:
ID: 3
Name: Alice
Age: 19

注：静态链表是指使用数组实现链表结构，相比于动态链表（使用指针实现），静态链表的空间利用率更高，但是插入和删除操作比较麻烦。