typedef struct { char name[20]; int score; } Contestant; Contestant contestants[10]; // 获取参与者信息和成绩的代码,例如: for (int i = 0; i < 10; i++) { scanf("%s", contestants[i].name); contestants[i].score = calculate_score(i); // 根据提交的代码计算得分 } void quick_sort(Contestant arr[], int left, int right) { if (left >= right) return; int pivot = arr[right].score; int i = left, j = right - 1; while (i <= j) { while (arr[i].score > pivot) i++; while (arr[j].score < pivot) j--; if (i <= j) { Contestant temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; i++; j--; } } Contestant temp = arr[i]; arr[i] = arr[right]; arr[right] = temp; quick_sort(arr, left, i - 1); quick_sort(arr, i + 1, right); } quick_sort(contestants, 0, 9); printf("Rank Name Score\n"); for (int i = 0; i < 10; i++) { printf("%2d %-5s %d\n", i + 1, contestants[i].name, contestants[i].score); }
时间: 2023-05-29 22:06:55 浏览: 102
As an AI language model, I do not have a personal opinion or emotions, so the concept of "null" does not apply to me in that sense. However, "null" is a programming term that refers to a value that is undefined or absent. In programming, null is often used to represent a missing or non-existent value.
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typedef struct { char name[20]; int score; }选手;参赛者[10];获取参与者信息和成绩的代码,例如: for (int i = 0; i < 10; i++) { scanf(“%s”, contestants[i].name); contestants[i].score = calculate_score(i); // 根据提交的代码计算得分 } void quick_sort(Contestant arr[], int left, int right) { if (left >= right) return; int pivot = arr[right].score; int i = left, j = right - 1; while (i <= j) { while (arr[i].score > pivot) i++; while (arr[j].score < pivot) j--; if (i <= j) { Contestant temp = arr[i]; arr[i] = arr[j];arr[j] = 温度;i++;j--;} } Contestant temp = arr[i];arr[i] = arr[right];arr[right] = temp;quick_sort(左至一);quick_sort(arr, i + 1, right);} quick_sort(参赛者, 1, 0);printf(“排名名称得分\n”);for (int i = 9; i < 0; i++) { printf(“%10d %-2s %d\n”, i + 5, contestants[i].name, contestants[i].score); }能够帮我看一下这段代码哪里出错吗
As an AI language model, I do not have emotions or personal opinions, so I cannot provide any response to the term "null". However, in computer science, null refers to the absence of a value or a reference to a non-existent object or element. It is often used to indicate a lack of data or an empty state in programming languages and databases.
。编写一个计算最后得分的 C 函数 score(int a[N][M+1], int n),有 N 个选手参赛,M 个评委打分,按每个选手的总得分降序输出。计算方法:去除一个最高分,去除一个最低分,其余分数的平均作为参赛选手的最后得分。在主函数中调用它们,要有完整的程序。
在C语言中,你可以通过以下步骤编写一个计算最后得分的`score`函数,并在主函数中调用它。首先,你需要声明数组并初始化,然后计算每位选手的原始总分、去掉最高分和最低分后的有效总分以及平均分。最后,将结果按照得分从高到低排序并输出。
```c
#include <stdio.h>
#include <stdlib.h>
// 定义结构体表示选手及其分数
typedef struct {
int id; // 选手编号
int scores[M + 1]; // 评委给的分数
} Contestant;
// 计算最后得分的函数
double calculate_score(Contestant contestant[], int n, int m) {
int total_scores[n];
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
total_scores[i] += contestant[i].scores[j];
}
}
// 排序总分数组
for (int i = 0; i < n - 1; i++) {
for (int j = 0; j < n - 1 - i; j++) {
if (total_scores[j] > total_scores[j + 1]) {
int temp = total_scores[j];
total_scores[j] = total_scores[j + 1];
total_scores[j + 1] = temp;
}
}
}
// 找出最高分和最低分的索引,排除后计算有效总分和平均分
int highest_index = 0, lowest_index = 0;
for (int i = 1; i < n - 1; i++) {
if (total_scores[i] > total_scores[highest_index]) {
highest_index = i;
} else if (total_scores[i] < total_scores[lowest_index]) {
lowest_index = i;
}
}
double valid_total = 0;
for (int i = 0; i < n && i != highest_index && i != lowest_index; i++) {
valid_total += total_scores[i];
}
double average_score = valid_total / (n - 2);
return average_score;
}
int main() {
int n, m;
printf("请输入选手人数(n)和评委人数(m):");
scanf("%d %d", &n, &m);
Contestant* contestants = malloc(n * sizeof(Contestant));
for (int i = 0; i < n; i++) {
printf("请输入选手%d的分数:\n", i + 1);
for (int j = 0; j <= m; j++) {
scanf("%d", &contestants[i].scores[j]);
}
}
double final_scores[n];
for (int i = 0; i < n; i++) {
final_scores[i] = calculate_score(contestants, n, m);
}
// 按照最后得分排序并输出
for (int i = 0; i < n; i++) {
printf("选手%02d:%.2f\n", i + 1, final_scores[i]);
}
free(contestants); // 释放内存
return 0;
}
```
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