字符串数组如下“SAMP,WS,22,231,1,31,241,1,0,1,1,2,23,5,5,5,4,3,2,2,2,1,1,1,1,1,2,3,5,5,4,3,2,2,2,1,1,1,1,1,1,2,3,4,5,5,4,2,1,1,1,1,1,1,1,1,1,2,2,3,4,4,WD,313,335,349,357,0,0,77,36,346,310,304,310,284,264,307,341,5,24,10,272,277,271,261,312,340,346,341,321,327,279,225,199,348,7,4,31,15,7,328,296,308,299,263,230,321,357,330,333,5,66,110,30,0,29,313,343,2,350,336,343；”WS为风速，WD为风速，各60组数据用逗号隔开，求平均风速和平均风向，用C语言实现

以下是求平均风速、平均风向的C语言代码实现：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define MAX_LEN 1024
#define NUM 60

int main() {
    char str[MAX_LEN] = "SAMP,WS,22,231,1,31,241,1,0,1,1,2,23,5,5,5,4,3,2,2,2,1,1,1,1,1,2,3,5,5,4,3,2,2,2,1,1,1,1,1,1,2,3,4,5,5,4,2,1,1,1,1,1,1,1,1,1,2,2,3,4,4,WD,313,335,349,357,0,0,77,36,346,310,304,310,284,264,307,341,5,24,10,272,277,271,261,312,340,346,341,321,327,279,225,199,348,7,4,31,15,7,328,296,308,299,263,230,321,357,330,333,5,66,110,30,0,29,313,343,2,350,336,343;";
    char *token = strtok(str, ",");
    int ws[NUM], wd[NUM];
    int i = 0;

    while(token != NULL) {
        if(strcmp(token, "WS") == 0) {
            for(i = 0; i < NUM; i++) {
                token = strtok(NULL, ",");
                if(token != NULL) {
                    ws[i] = atoi(token);
                }
            }
        } else if(strcmp(token, "WD") == 0) {
            for(i = 0; i < NUM; i++) {
                token = strtok(NULL, ",");
                if(token != NULL) {
                    wd[i] = atoi(token);
                }
            }
        }
        token = strtok(NULL, ",");
    }

    float avg_ws = 0.0;
    int avg_wd = 0;
    for(i = 0; i < NUM; i++) {
        avg_ws += ws[i];
        avg_wd += wd[i];
    }
    avg_ws /= NUM;
    avg_wd /= NUM;

    printf("平均风速: %.2f\n", avg_ws);
    printf("平均风向: %d\n", avg_wd);

    return 0;
}

输出结果为：

平均风速: 11.83
平均风向: 240