输入整数n在一行内从小到大排序前n个回文素数
时间: 2024-05-09 09:21:19 浏览: 7
暂不支持中文模型,以下为英文回答:
To solve this problem, we need to first define what a palindrome prime is. A palindrome prime is a prime number that is also a palindrome number, which means that it reads the same from left to right as from right to left.
Now, we can start by generating all prime numbers up to a certain limit, and then checking which of these primes are also palindrome numbers. Here is a Python code that does this:
```python
def is_prime(n):
if n < 2:
return False
for i in range(2, int(n**0.5) + 1):
if n % i == 0:
return False
return True
def is_palindrome(n):
return str(n) == str(n)[::-1]
n = int(input())
count = 0
i = 2
while count < n:
if is_prime(i) and is_palindrome(i):
print(i, end=" ")
count += 1
i += 1
```
In this code, the `is_prime` function checks whether a given number is prime or not using a simple trial division algorithm. The `is_palindrome` function checks whether a given number is a palindrome number by converting it to a string and comparing it with its reversed string.
The main loop then generates prime numbers starting from 2, and checks whether each number is a palindrome prime. Once `n` palindrome primes have been found, the loop stops and the program prints the list of palindrome primes in ascending order.
Note that this code may not be very efficient for large values of `n`, since it generates all prime numbers up to `n` and checks each of them for palindrome-ness. A more efficient approach would be to use a sieve algorithm to generate only the first `n` primes, and then check each of these primes for palindrome-ness.