4.试完成如下几个程序设计步骤： （1）编写一个子两数实现月份输出，其输出效果如下： 33 C:\Windows\system32\cmd.exe 锋出月份？ January lebruary March April May June July August September Detober November 清校崔意健牲缘 (2)再编写一个子两数实现月份按宇符串顺序排列，并将排序结果进行输出， 其程序结构如下： #include <iostream> using namespace std; void DispMonths (char p[J [30]) //打印12个月份 void SortStrings (char p[] [30], int n) int main () { 1/months的定义及用字符串初始化的过程 char months [12] [30]=("January", "February", "*) cout<<“排序前：”<<endl; DispMonths (months); SortStrings (months, 12); cout<Cendl<<〞排序后：“<<endl: DispMonths (months); return 0; 其效果图为

(1) 子函数实现月份输出：

#include <iostream>
using namespace std;

void DispMonths() {
    char months[12][10] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
    for(int i = 0; i < 12; i++) {
        cout << months[i] << " ";
    }
}

int main() {
    DispMonths();
    return 0;
}

输出结果：

January February March April May June July August September October November December

(2) 子函数实现月份按字母顺序排列并输出：

#include <iostream>
#include <cstring>
using namespace std;

void DispMonths(char p[][30], int n) {
    for(int i = 0; i < n; i++) {
        cout << p[i] << " ";
    }
    cout << endl;
}

void SortStrings(char p[][30], int n) {
    for(int i = 0; i < n - 1; i++) {
        for(int j = i + 1; j < n; j++) {
            if(strcmp(p[i], p[j]) > 0) {
                char temp[30];
                strcpy(temp, p[i]);
                strcpy(p[i], p[j]);
                strcpy(p[j], temp);
            }
        }
    }
}

int main() {
    char months[12][30] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
    cout << "排序前：" << endl;
    DispMonths(months, 12);
    SortStrings(months, 12);
    cout << "排序后：" << endl;
    DispMonths(months, 12);
    return 0;
}

输出结果：

排序前：
January February March April May June July August September October November December 
排序后：
April August December February January July June March May November October September