在一个结构体数组中存有3个人的姓名和年龄，输出3个人中年龄居中者的姓名和年龄。 要求： ① 3个人的数据采用直接初始化的方式赋值。 ② 利用结构体指针实现处理过程。

以下是实现代码：

#include <stdio.h>

struct Person {
    char name[20];
    int age;
};

int main() {
    struct Person people[3] = {{"Tom", 20}, {"Jerry", 30}, {"Mike", 25}};
    struct Person *p = people;
    int max_age = p->age, min_age = p->age, mid_age = p->age;
    struct Person *max_p = p, *min_p = p, *mid_p = p;

    for (int i = 0; i < 3; i++) {
        if ((p + i)->age > max_age) {
            max_age = (p + i)->age;
            max_p = p + i;
        }
        if ((p + i)->age < min_age) {
            min_age = (p + i)->age;
            min_p = p + i;
        }
    }

    for (int i = 0; i < 3; i++) {
        struct Person *temp = p + i;
        if (temp != max_p && temp != min_p) {
            mid_age = temp->age;
            mid_p = temp;
        }
    }

    printf("The person with middle age is %s and he/she is %d years old.\n", mid_p->name, mid_p->age);

    return 0;
}

运行结果：

The person with middle age is Mike and he/she is 25 years old.