生成一个布谷鸟算法的代码
时间: 2024-05-07 08:23:54 浏览: 97
以下是一个简单的布谷鸟算法的 Python 代码实现。您可以将其用作参考并扩展它以满足您的需求。
```
import random
# 参数设置
population_size = 20
max_generation = 100
num_variables = 10
low_bound = -10
up_bound = 10
# 布谷鸟生成函数
def generate_bird():
bird = {
"position": [random.uniform(low_bound, up_bound) for _ in range(num_variables)],
"fitness": None,
"num_flights": 0
}
return bird
# 评估函数
def evaluate_bird(bird):
# 您的评估函数代码在这里
return bird["fitness"]
# 布谷鸟搜索函数
def cuckoo_search():
# 初始化种群
population = [generate_bird() for _ in range(population_size)]
# 计算每个布谷鸟的适应度
for bird in population:
bird["fitness"] = evaluate_bird(bird)
# 开始搜索
generation = 0
while generation < max_generation:
# 选择一个随机的布谷鸟
random_bird_index = random.randint(0, population_size-1)
random_bird = population[random_bird_index]
# 生成新的布谷鸟并计算适应度
new_bird = generate_bird()
new_bird["fitness"] = evaluate_bird(new_bird)
# 如果新的布谷鸟更优,则替换当前布谷鸟
if new_bird["fitness"] > random_bird["fitness"]:
population[random_bird_index] = new_bird
# 对当前种群按适应度排序
population = sorted(population, key=lambda x: x["fitness"], reverse=True)
# 随机替换部分布谷鸟
num_replaced_birds = int(0.2 * population_size)
for i in range(num_replaced_birds):
population[-(i+1)] = generate_bird()
# 增加布谷鸟的飞行次数
for bird in population:
bird["num_flights"] += 1
# 增加代数
generation += 1
# 返回最优布谷鸟
return population[0]
```
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