下面android代码是上传的照片，现在要求上传完后吧照片从相册里删掉，怎么做？ private void doSubmitUpload_W() { Map<String, Object> uploadparams = null; try { if ((mPgDialog != null) && mPgDialog.isShowing()) { mPgDialog.dismiss(); } mPgDialog = createPhotoDialog_W(R.string.photo_uploading_and_wait); mPgDialog.show(); uploadCallback_w = new AjaxCallback<JSONObject>() { @Override public void callback(String url, JSONObject json, AjaxStatus status) { if ((mPgDialog != null) && mPgDialog.isShowing()) { TakeTxPhotoActivity.this.mPgDialog.dismiss(); } // 解析结果 TakeTxPhotoActivity.this.parseUploadResult_w(url, json, status); } }; Long staffId = SessionManager.getInstance().getStaffId() == null?-1L:SessionManager.getInstance().getStaffId(); uploadparams = new HashMap<String, Object>();// ParamHelper.buildJSONParam(URLs.UPLOADFILE_API,json); byte[] photots = Bitmap2Bytes(ImageUtils.getBitmapByPath(mWorkAdapter.get( curPhotoPos_W).getThumbnailPath())); uploadparams.put("photoFile2",photots); uploadparams.put("StaffId", staffId); uploadparams.put("StaffName", session.getStaffInfo().getStaffName()); uploadparams.put("OrderID", orderId); uploadparams.put("WorkOrderID", workOrderId); uploadparams.put("TypeName", "WORK"); uploadparams.put("photosType", mWorkAdapter.get(curPhotoPos_W).getPhotosType()); Log.e(TAG, "请求参数json:" + uploadparams.toString()); // 异步网络请求 aQuery.ajax(BaseURLs.UPLOAD_KT_PHOTO, uploadparams, JSONObject.class, uploadCallback_w); } catch (Exception ex) { AlertUtils.showAlert(TakeTxPhotoActivity.this, R.string.opt_prompt, R.string.unknown_error); ex.printStackTrace(); } }

您可以在上传照片的回调方法中添加删除照片的逻辑。在`callback`方法中，您可以使用以下代码删除照片：

File photoFile = new File(mWorkAdapter.get(curPhotoPos_W).getThumbnailPath());
boolean deleted = photoFile.delete();
if (deleted) {
    Log.e(TAG, "照片删除成功");
} else {
    Log.e(TAG, "照片删除失败");
}

将上面的代码添加到`callback`方法的开始部分，即可在上传完毕后删除照片。请确保`mWorkAdapter.get(curPhotoPos_W).getThumbnailPath()`返回的是照片文件的路径。

相关问题

flask mongodb文件的上传 上传文件 文件名重复的删掉 前后端代码

前端代码：

<form method="POST" enctype="multipart/form-data">
  <input type="file" name="file">
  <input type="submit" value="Upload">
</form>

后端代码：

from flask import Flask, request
from pymongo import MongoClient
import os

app = Flask(__name__)

# 连接MongoDB
client = MongoClient('localhost', 27017)
db = client['test']
collection = db['files']

# 上传文件
@app.route('/upload', methods=['POST'])
def upload_file():
    file = request.files['file']
    # 判断文件名是否重复
    if collection.find_one({'name': file.filename}):
        return 'File already exists!'
    else:
        # 保存文件
        file.save(os.path.join(app.config['UPLOAD_FOLDER'], file.filename))
        # 将文件信息存入MongoDB
        collection.insert_one({'name': file.filename,
                               'path': os.path.join(app.config['UPLOAD_FOLDER'], file.filename)})
        return 'File uploaded successfully!'

if __name__ == '__main__':
    app.config['UPLOAD_FOLDER'] = '/path/to/upload/folder'
    app.run()

注意：需要安装pymongo模块。

我有一个txt文件，里面有很多组数据，如果某一行中含有“_inv”就删掉一整行，帮我撰写python代码

当然可以，以下是一个简单的Python代码来实现你的要求：

with open('file.txt', 'r') as file:
    lines = file.readlines()

with open('new_file.txt', 'w') as new_file:
    for line in lines:
        if '_inv' not in line:
            new_file.write(line)

这个代码将会读取名为 `file.txt` 的文件，然后逐行检查是否包含 `_inv`，如果不包含就将这一行写到名为 `new_file.txt` 的新文件中。