pyton石头剪刀布人机对垒代码

好的，下面是Python实现的石头剪刀布人机对垒代码：

import random

# 定义石头剪刀布的列表
gesture = ['石头', '剪刀', '布']

# 取玩家的输入
player = input("请输入石头, 剪刀, 布：")

# 取电脑的输入
computer = random.choice(gesture)

# 输出电脑的选择
print("电脑选择了：", computer)

# 判断胜负
if player == computer:
    print("平局")
elif player == '石头' and computer == '剪刀' \
    or player == '剪刀' and computer == '布' \
    or player == '布' and computer == '石头':
    print("你赢了")
else:
    print("电脑赢了")

希望对你有帮助！如果有其他问题，欢迎继续提问。