VHDL语言30MHz分频为1Hz实现32个LED流水灯
时间: 2024-03-10 12:51:21 浏览: 109
好的,让我来回答你的问题。首先,我们可以使用一个计数器来生成分频信号。我们可以使用VHDL语言编写一个计数器模块,将输入时钟信号分频为1Hz的信号。然后,我们可以使用一个移位寄存器来控制32个LED的流水灯效果。
以下是示例代码:
计数器模块:
```
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
entity divider is
Port (
clk : in std_logic;
reset : in std_logic;
clk_out : out std_logic
);
end divider;
architecture Behavioral of divider is
signal count : integer range 0 to 29999999 := 0;
begin
process (clk, reset)
begin
if reset = '1' then
count <= 0;
clk_out <= '0';
elsif rising_edge(clk) then
count <= count + 1;
if count = 29999999 then -- 30MHz时钟信号分频为1Hz
count <= 0;
clk_out <= '1';
else
clk_out <= '0';
end if;
end if;
end process;
end Behavioral;
```
LED流水灯模块:
```
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
entity led_shift_reg is
Port (
clk : in std_logic;
reset : in std_logic;
shift_in : in std_logic;
leds : out std_logic_vector(31 downto 0)
);
end led_shift_reg;
architecture Behavioral of led_shift_reg is
signal shift_reg : std_logic_vector(31 downto 0) := (others => '0');
begin
process (clk, reset)
begin
if reset = '1' then
shift_reg <= (others => '0');
elsif rising_edge(clk) then
shift_reg <= shift_reg(30 downto 0) & shift_in; -- 移位
end if;
end process;
leds <= shift_reg;
end Behavioral;
```
最后,我们将两个模块组合在一起:
```
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
entity led_controller is
Port (
clk : in std_logic;
reset : in std_logic;
leds : out std_logic_vector(31 downto 0)
);
end led_controller;
architecture Behavioral of led_controller is
signal clk_out : std_logic := '0';
signal shift_in : std_logic := '1';
begin
divider_inst : entity work.divider
port map (
clk => clk,
reset => reset,
clk_out => clk_out
);
shift_reg_inst : entity work.led_shift_reg
port map (
clk => clk_out,
reset => reset,
shift_in => shift_in,
leds => leds
);
process (clk)
begin
if rising_edge(clk) then
shift_in <= not shift_in; -- 控制LED灯流动方向
end if;
end process;
end Behavioral;
```
这样,我们就实现了一个可以控制32个LED灯流水的VHDL模块。注意,这只是一个简单的示例,您可能需要根据您的实际需求进行适当的修改。
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