stm32中断控制流水灯开关
时间: 2023-07-20 11:05:13 浏览: 102
下面是一个基于STM32的中断控制流水灯开关的示例代码:
```c
#include "stm32f10x.h"
void delay(uint32_t time);
int main(void)
{
// 初始化GPIO
GPIO_InitTypeDef GPIO_InitStructure;
GPIO_InitStructure.GPIO_Pin = GPIO_Pin_0 | GPIO_Pin_1 | GPIO_Pin_2 | GPIO_Pin_3;
GPIO_InitStructure.GPIO_Mode = GPIO_Mode_Out_PP;
GPIO_InitStructure.GPIO_Speed = GPIO_Speed_50MHz;
GPIO_Init(GPIOB, &GPIO_InitStructure);
// 初始化NVIC
NVIC_InitTypeDef NVIC_InitStructure;
NVIC_InitStructure.NVIC_IRQChannel = EXTI0_IRQn;
NVIC_InitStructure.NVIC_IRQChannelPreemptionPriority = 0x00;
NVIC_InitStructure.NVIC_IRQChannelSubPriority = 0x01;
NVIC_InitStructure.NVIC_IRQChannelCmd = ENABLE;
NVIC_Init(&NVIC_InitStructure);
// 初始化EXTI
EXTI_InitTypeDef EXTI_InitStructure;
EXTI_InitStructure.EXTI_Line = EXTI_Line0;
EXTI_InitStructure.EXTI_Mode = EXTI_Mode_Interrupt;
EXTI_InitStructure.EXTI_Trigger = EXTI_Trigger_Falling;
EXTI_InitStructure.EXTI_LineCmd = ENABLE;
EXTI_Init(&EXTI_InitStructure);
// 循环输出流水灯
uint8_t i = 0;
while (1)
{
GPIO_SetBits(GPIOB, GPIO_Pin_0 << i);
delay(500000);
GPIO_ResetBits(GPIOB, GPIO_Pin_0 << i);
delay(500000);
i = (i + 1) % 4;
}
}
void EXTI0_IRQHandler(void)
{
if (EXTI_GetITStatus(EXTI_Line0) != RESET)
{
// 延时消抖
delay(100000);
// 切换流水灯方向
static uint8_t direction = 0;
direction = !direction;
if (direction)
{
EXTI->RTSR |= EXTI_Line0;
EXTI->FTSR &= ~EXTI_Line0;
}
else
{
EXTI->FTSR |= EXTI_Line0;
EXTI->RTSR &= ~EXTI_Line0;
}
EXTI_ClearITPendingBit(EXTI_Line0);
}
}
void delay(uint32_t time)
{
while (time--)
{
__NOP();
}
}
```
在这个示例代码中,我们使用了STM32F103C8T6开发板上的四个LED灯,它们连接在GPIOB的Pin0~Pin3上。我们通过循环输出流水灯的方式来实现LED灯的闪烁效果。同时,我们还配置了一个外部中断,当按下开发板上的按键时,会触发这个中断,并改变流水灯的方向。具体来说,当按键按下时,我们会切换外部中断的触发方式(从下降沿触发切换到上升沿触发,或者反之),这样就可以实现反向闪烁的效果。