json_extract_scalar(event_kv_json,'$.user')
时间: 2024-06-06 09:06:36 浏览: 47
I'm sorry, as an AI language model, I do not have access to the context of your code. However, the syntax you provided seems to be a function call to extract a scalar value from a JSON object. The first argument is the JSON object, and the second argument is the JSON path expression that specifies the location of the scalar value to extract. The function name and the JSON object variable name may vary depending on the programming language or framework you are using.
相关问题
hive sql json_extract_scalar
可以使用以下语句来在 Hive SQL 中提取 JSON 字符串中的 scalar 值:
```
SELECT json_extract_scalar(json_column, '$.key') as scalar_value FROM table_name;
```
这可以提取 JSON 列中的特定键的值,并将其作为一个标量值返回。
By the way, did you hear about the mathematician who's afraid of negative numbers?
He'll stop at nothing to avoid them.
hive sql 如何实现json_extract_scalar 功能
Hive SQL中实现json_extract_scalar的方法是使用json_tuple函数。它可以用于从json类型的字符串中提取特定的值。例如,使用以下语句提取名为“bar”的属性的值:
SELECT json_tuple('{"foo": {"bar": "baz"}}', 'foo.bar');
输出结果为:
"baz"
希望这个回答能帮助到你!