下面程序输出结果为: Display1() in BaseClass is called! Display1() in DerivedClass is called! Display2() in BaseClass is called! Display2() in BaseClass is called! 请将程序填写完整 #include <iostream> using namespace std; class BaseClass { public: (1) {cout<<"Display1() in BaseClass is called!"<<endl;} (2) {cout<<"Display2() in BaseClass is called!"<<endl;} }; class DerivedClass:public BaseClass { public: void Display1(){cout<<"Display1() in DerivedClass is called!"<<endl;} void Display2(){cout<<"Display2() in DerivedClass is called!"<<endl;} }; void fun1( (3) ) { p->Display1(); } void fun2(BaseClass &rb) { rb.Display2(); } int main() { BaseClass b; DerivedClass d; fun1(&b); fun1(&d); fun2(b); fun2(d); return 0; }
时间: 2024-04-01 15:33:38 浏览: 113
#include <iostream>
using namespace std;
class BaseClass {
public:
void Display1() {cout<<"Display1() in BaseClass is called!"<<endl;}
void Display2() {cout<<"Display2() in BaseClass is called!"<<endl;}
};
class DerivedClass:public BaseClass {
public:
void Display1() {cout<<"Display1() in DerivedClass is called!"<<endl;}
void Display2() {cout<<"Display2() in DerivedClass is called!"<<endl;}
};
void fun1(BaseClass *p) {
p->Display1();
}
void fun2(BaseClass &rb) {
rb.Display2();
}
int main() {
BaseClass b;
DerivedClass d;
fun1(&b);
fun1(&d);
fun2(b);
fun2(d);
return 0;
}
相关问题
Using C++, Define a Shape class and its subclasses Circle and Rectangle. The detailed requirements are: (1) Data members: a) Shape's data members include: name, color. b) Circle has an additional data member: radius. c) Rectangle has two additional data members: width, height. (2) Member functions: a) Each class should have a constructor to initialize its data members. b) Define in each class a function show() to display its data members. (3) A global function "showShape(const Shape &shape)" to call a Shape object’s show() function t o display its content. (4) The main() function: a) Define a Circle object circle1 and a Rectangle object rectangle1. b) Define a Shape pointer p_shape to point to circle1, and call showShape(*p_shape) to displ ay the circle's information. c) Change p_shape to point to rectangle1, and call showShape(*p_shape) to display the recta ngle's information.
Sure, here's an implementation of the Shape, Circle, and Rectangle classes in C++:
```c++
#include <iostream>
#include <string>
using namespace std;
class Shape {
protected:
string name;
string color;
public:
Shape(string n, string c) : name(n), color(c) {}
virtual void show() {
cout << "Name: " << name << endl;
cout << "Color: " << color << endl;
}
};
class Circle : public Shape {
private:
double radius;
public:
Circle(string n, string c, double r) : Shape(n, c), radius(r) {}
void show() {
Shape::show();
cout << "Radius: " << radius << endl;
}
};
class Rectangle : public Shape {
private:
double width;
double height;
public:
Rectangle(string n, string c, double w, double h) : Shape(n, c), width(w), height(h) {}
void show() {
Shape::show();
cout << "Width: " << width << endl;
cout << "Height: " << height << endl;
}
};
void showShape(const Shape& shape) {
shape.show();
}
int main() {
Circle circle1("Circle 1", "Red", 5.0);
Rectangle rectangle1("Rectangle 1", "Blue", 3.0, 4.0);
Shape* p_shape = &circle1;
showShape(*p_shape);
p_shape = &rectangle1;
showShape(*p_shape);
return 0;
}
```
In this implementation, the Shape class is a base class with two data members: name and color. The Circle and Rectangle classes are subclasses of Shape, and they add additional data members: radius for Circle and width and height for Rectangle. Each class has its own constructor to initialize its data members, and a show() function to display its data members. The show() function in the base class is declared as virtual so that the derived classes can override it.
The global function showShape() takes a Shape object as a parameter and calls its show() function to display its content.
In the main() function, a Circle object and a Rectangle object are defined. A Shape pointer p_shape is first pointed to circle1 and showShape(*p_shape) is called to display the circle's information. Then, p_shape is changed to point to rectangle1, and showShape(*p_shape) is called to display the rectangle's information.
systemverilog中如何调用其他class中的定义的参数
在SystemVerilog中,如果你想要在类(class)之间传递参数并调用另一个类的方法,你可以通过构造函数传参或者类成员函数间接访问。这里是一个基本的例子:
```systemverilog
// 定义一个基础类 BaseClass
class BaseClass {
parameter some_param = 0; // 类参数
function void method();
$display("BaseClass method called with param: %d", some_param);
endfunction
};
// 另一个类 DerivedClass 继承自 BaseClass 并可以接收并使用参数
class DerivedClass extends BaseClass {
function DerivedClass(int param_to_pass); // 构造函数接受外部参数
this.some_param = param_to_pass; // 将参数赋值给基类的参数
endfunction
};
// 使用DerivedClass时,通过构造函数传入参数
module top;
DerivedClass my_obj(5); // 传递参数5给DerivedClass的构造函数
initial begin
my_obj.method(); // 调用基类的方法,并使用传入的参数
end
endmodule
```
在这个例子中,`my_obj.method()`会打印出"BaseClass method called with param: 5",因为我们在创建DerivedClass实例时传递了参数。
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