按键3松开时,蜂鸣器响5声,以上均不支持连续触发,按键2按下时,一位静态数码管显示5,按键1按下时,实现自左向右流水灯;
时间: 2024-05-10 07:21:32 浏览: 104
以下是Python代码实现:
```python
import RPi.GPIO as GPIO
import time
# 设置GPIO模式为BCM编码方式
GPIO.setmode(GPIO.BCM)
# 定义按键和蜂鸣器的GPIO口
key1 = 18
key2 = 23
key3 = 24
buzzer = 25
# 定义数码管的GPIO口
# 按照a,b,c,d,e,f,g,dp的顺序排列
digit_pins = [4, 17, 27, 22, 5, 6, 13, 19]
# 定义数码管显示的数字
# 按照0,1,2,3,4,5,6,7,8,9,a,b,c,d,e,f的顺序排列
digit_num = [
[1, 1, 1, 1, 1, 1, 0, 0], # 0
[0, 1, 1, 0, 0, 0, 0, 0], # 1
[1, 1, 0, 1, 1, 0, 1, 0], # 2
[1, 1, 1, 1, 0, 0, 1, 0], # 3
[0, 1, 1, 0, 0, 1, 1, 0], # 4
[1, 0, 1, 1, 0, 1, 1, 0], # 5
[1, 0, 1, 1, 1, 1, 1, 0], # 6
[1, 1, 1, 0, 0, 0, 0, 0], # 7
[1, 1, 1, 1, 1, 1, 1, 0], # 8
[1, 1, 1, 1, 0, 1, 1, 0], # 9
[1, 1, 1, 0, 1, 1, 1, 0], # a
[0, 0, 1, 1, 1, 1, 1, 0], # b
[1, 0, 0, 1, 1, 1, 0, 0], # c
[0, 1, 1, 1, 1, 0, 1, 0], # d
[1, 0, 0, 1, 1, 1, 1, 0], # e
[1, 0, 0, 0, 1, 1, 1, 0], # f
]
# 初始化GPIO口
GPIO.setup(key1, GPIO.IN, pull_up_down=GPIO.PUD_UP)
GPIO.setup(key2, GPIO.IN, pull_up_down=GPIO.PUD_UP)
GPIO.setup(key3, GPIO.IN, pull_up_down=GPIO.PUD_UP)
GPIO.setup(buzzer, GPIO.OUT)
for pin in digit_pins:
GPIO.setup(pin, GPIO.OUT)
# 定义按键和蜂鸣器的状态变量
key1_pressed = False
key2_pressed = False
key3_pressed = False
buzzer_on = False
# 定义数码管显示的数字变量
digit_index = 0
# 定义流水灯的状态变量
led_index = 0
# 定义流水灯的方向变量
led_direction = 1
# 循环执行
while True:
# 检测按键1的状态
if GPIO.input(key1) == GPIO.LOW:
key1_pressed = True
else:
if key1_pressed:
key1_pressed = False
# 按键1按下时,实现自左向右流水灯
GPIO.output(digit_pins[led_index], GPIO.LOW)
led_index += led_direction
if led_index == len(digit_pins):
led_index = len(digit_pins) - 2
led_direction = -1
elif led_index == -1:
led_index = 1
led_direction = 1
GPIO.output(digit_pins[led_index], GPIO.HIGH)
# 检测按键2的状态
if GPIO.input(key2) == GPIO.LOW:
key2_pressed = True
else:
if key2_pressed:
key2_pressed = False
# 按键2按下时,一位静态数码管显示5
for i in range(len(digit_pins)):
GPIO.output(digit_pins[i], digit_num[5][i])
# 检测按键3的状态
if GPIO.input(key3) == GPIO.LOW:
key3_pressed = True
else:
if key3_pressed:
key3_pressed = False
# 按键3松开时,蜂鸣器响5声
for i in range(5):
GPIO.output(buzzer, GPIO.HIGH)
time.sleep(0.1)
GPIO.output(buzzer, GPIO.LOW)
time.sleep(0.1)
# 数码管显示的数字循环加1
digit_index += 1
if digit_index == 16:
digit_index = 0
# 数码管显示的数字变化
for i in range(len(digit_pins)):
GPIO.output(digit_pins[i], digit_num[digit_index][i])
# 延时一段时间
time.sleep(0.1)
# 清理GPIO口
GPIO.cleanup()
```
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