c++输入5个数求离均差

非常感谢您的提问。以下是求离均差的代码：

#include <stdio.h>
#include <math.h>

int main()
{
    int n = 5;
    double sum = 0, avg, diff_sum = 0;

    printf("请输入%d个数：\n", n);
    for (int i = 0; i < n; i++) {
        double num;
        scanf("%lf", &num);
        sum += num;
    }

    avg = sum / n;

    for (int i = 0; i < n; i++) {
        double num;
        scanf("%lf", &num);
        diff_sum += fabs(num - avg);
    }

    double result = diff_sum / n;
    printf("离均差为：%lf\n", result);

    return 0;
}

希望能够帮到您！