根据行数列数左上角右上角右下角算出矩阵所有坐标及间距,要求C Shap语言实现并带注释
时间: 2023-05-31 19:04:39 浏览: 10
以下是C#语言实现的代码,其中注释解释了每一步的操作:
```csharp
using System;
class Program
{
static void Main(string[] args)
{
int rows = 3; // 矩阵行数
int cols = 4; // 矩阵列数
int leftTop = 1; // 左上角元素
int rightTop = 4; // 右上角元素
int rightBottom = 9; // 右下角元素
// 计算每个元素之间的行、列间距
int rowSpacing = (rightBottom - leftTop) / (rows - 1);
int colSpacing = (rightTop - leftTop) / (cols - 1);
// 遍历每个元素,根据左上角元素和间距计算出坐标
for (int row = 0; row < rows; row++)
{
for (int col = 0; col < cols; col++)
{
int num = leftTop + row * rowSpacing + col * colSpacing;
Console.Write(num + " ");
}
Console.WriteLine();
}
}
}
```
输出结果为:
```
1 2 3 4
5 6 7 8
9 10 11 12
```
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