在windows上添加一条目标地址为192.168.100.219,网关为192.168.48.2的路由
时间: 2024-04-08 13:30:31 浏览: 145
在 Windows 上添加路由可以使用`route`命令。要添加一条目标地址为192.168.100.219,网关为192.168.48.2的路由,可以按照以下步骤操作:
1. 打开命令提示符(CMD)或 PowerShell。
2. 输入以下命令并按Enter键执行:
```
route add 192.168.100.219 mask 255.255.255.255 192.168.48.2
```
这条命令将添加一条静态路由,将目标地址192.168.100.219的流量发送到网关192.168.48.2。
请注意,这是一条临时路由,系统重启后将失效。如果需要在系统重启后保留该路由,可以使用`-p`参数,如下所示:
```
route -p add 192.168.100.219 mask 255.255.255.255 192.168.48.2
```
此命令将使路由在系统重启后保持有效。
请确保目标地址和网关的IP地址是正确的,并根据实际情况进行相应的调整。
相关问题
1.某市欲调查该市个体商业户全年的销售额,利用工商管理局的资料确定调查的样本单元.该市有个体商业户 10000 户,准备抽取200户做实地调查.为提高精度采用二重分层方法.先在 10000 户中抽取 2000户,查阅各户的注册资金,按注册资金将这 2000 户分为5层,再从每层抽取 1/10的户实地调查.有关数据如下: 层 第一重样本量 第二重样本量 第二重样本年销量均值(万元) 5万元以下 1000 100 4.2 5~10万元 620 62 10.7 11~20万元 200 20 24.0 21~40万元 100 10 35.6 40万元以上 80 8 48.2 总计 2000 200 试估计该市全年个体商业户的销售总额
根据题目所给的数据,我们可以得到每个样本单元的加权平均数,再根据二重分层抽样的方法进行估计。
首先,计算每个分层中抽样单元的总数:
- 5万元以下:1000 × 1/10 = 100
- 5~10万元:620 × 1/10 = 62
- 11~20万元:200 × 1/10 = 20
- 21~40万元:100 × 1/10 = 10
- 40万元以上:80 × 1/10 = 8
然后,计算每个分层中抽样单元的加权平均数:
- 5万元以下:4.2 × 100 = 420
- 5~10万元:10.7 × 62 = 663.4
- 11~20万元:24.0 × 20 = 480
- 21~40万元:35.6 × 10 = 356
- 40万元以上:48.2 × 8 = 385.6
最后,将每个分层的加权平均数相加,得到总体的加权平均数:
420 + 663.4 + 480 + 356 + 385.6 = 2305
因此,该市全年个体商业户的销售总额的估计值为 2305 万元。
model: sets: gch/1..7/:p,s; gd/1..15/:A,y,z; links(gch,gd):x,c; endsets data: p = 160 155 155 160 155 150 160; s = 800 800 1000 2000 2000 2000 3000; c = 170.7 160.3 140.2 98.6 38 20.5 3.1 21.2 64.2 92 96 106 121.2 128 142 215.7 205.3 190.2 171.6 111 95.5 86 71.2 114.2 142 146 156 171.2 178 192 230.7 220.3 200.2 181.6 121 105.5 96 86.2 48.2 82 86 96 111.2 118 132 260.7 250.3 235.2 216.6 156 140.5 131 116.2 84.2 62 51 61 76.2 83 97 255.7 245.3 225.2 206.6 146 130.5 121 111.2 79.2 57 33 51 71.2 73 87 265.7 255.3 235.2 216.6 156 140.5 131 121.2 84.2 62 51 45 26.2 11 28 275.7 265.3 245.2 226.6 166 150.5 141 131.2 99.2 76 66 56 38.2 26 2; enddata min = W + Q + T; W = @sum(links(i,j):p(i)*x(i,j)); Q = @sum(links(i,j):c(i,j)*x(i,j)); T = @sum(gd(j):(1+y(j))*y(j)+(1+z(j))*z(j))*0.05; z(1)+y(2)=104 ; z(2)+y(3)=301 ; z(3)+y(4)=750 ; z(4)+y(5)=606 ; z(5)+y(6)=194 ; z(6)+y(7)=205; z(7)+y(8)=201; z(8)+y(9)=680; z(9)+y(10)=480; z(10)+y(11)=300; z(11)+y(12)=220; z(12)+y(13)=210; z(13)+y(14)=420; z(14)+y(15)=500; y(1)+z(1) = @sum(gch(i):x(i,1)); y(2)+z(2) = @sum(gch(i):x(i,2)); y(3)+z(3) = @sum(gch(i):x(i,3)); y(4)+z(4) = @sum(gch(i):x(i,4)); y(5)+z(5) = @sum(gch(i):x(i,5)); y(6)+z(6) = @sum(gch(i):x(i,6)); y(7)+z(7) = @sum(gch(i):x(i,7)); y(8)+z(8) = @sum(gch(i):x(i,8)); y(9)+z(9) = @sum(gch(i):x(i,9)); y(10)+z(10) = @sum(gch(i):x(i,10)); y(11)+z(11) = @sum(gch(i):x(i,11)); y(12)+z(12) = @sum(gch(i):x(i,12)); y(13)+z(13) = @sum(gch(i):x(i,13)); y(14)+z(14) = @sum(gch(i):x(i,14)); y(15)+z(15) = @sum(gch(i):x(i,15)); @for(gch(i):@sum(gd(j):x(i,j))<=s(i)); end 请将上述Lingo编程转换为GAMS语言
以下是将Lingo代码转换为GAMS语言的代码:
```
SETS
gch /1*7/
gd /1*15/;
PARAMETERS
p(gch)
s(gch)
c(gch, gd);
VARIABLES
x(gch, gd)
y(gd)
z(gd)
W
Q
T;
MINIMIZE
W + Q + T;
W.EQUATION
W = SUM((gch, gd), p(gch) * x(gch, gd));
Q.EQUATION
Q = SUM((gch, gd), c(gch, gd) * x(gch, gd));
T.EQUATION
T = SUM(gd, ((1 + y(gd)) * y(gd) + (1 + z(gd)) * z(gd)) * 0.05);
z('1') + y('2') = 104;
z('2') + y('3') = 301;
z('3') + y('4') = 750;
z('4') + y('5') = 606;
z('5') + y('6') = 194;
z('6') + y('7') = 205;
z('7') + y('8') = 201;
z('8') + y('9') = 680;
z('9') + y('10') = 480;
z('10') + y('11') = 300;
z('11') + y('12') = 220;
z('12') + y('13') = 210;
z('13') + y('14') = 420;
z('14') + y('15') = 500;
y('1') + z('1') = SUM(gch, x(gch, '1'));
y('2') + z('2') = SUM(gch, x(gch, '2'));
y('3') + z('3') = SUM(gch, x(gch, '3'));
y('4') + z('4') = SUM(gch, x(gch, '4'));
y('5') + z('5') = SUM(gch, x(gch, '5'));
y('6') + z('6') = SUM(gch, x(gch, '6'));
y('7') + z('7') = SUM(gch, x(gch, '7'));
y('8') + z('8') = SUM(gch, x(gch, '8'));
y('9') + z('9') = SUM(gch, x(gch, '9'));
y('10') + z('10') = SUM(gch, x(gch, '10'));
y('11') + z('11') = SUM(gch, x(gch, '11'));
y('12') + z('12') = SUM(gch, x(gch, '12'));
y('13') + z('13') = SUM(gch, x(gch, '13'));
y('14') + z('14') = SUM(gch, x(gch, '14'));
y('15') + z('15') = SUM(gch, x(gch, '15'));
SUBJECT TO
capacity(gch)..
SUM(gd, x(gch, gd)) <= s(gch);
MODEL transportation /ALL/;
SOLVE transportation USING LP MINIMIZING W;
```
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