用java计算：输入任意正整数n，代入此公式：(10/2的阶乘)+(20/4的阶乘)+(40/6的阶乘)+……+[(10*2的n次方)/(2*n的阶乘)]，输出答案

好的，我来为您写一段Java代码来计算这个公式：

import java.math.BigInteger;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = scanner.nextInt();

        BigInteger sum = BigInteger.valueOf(0);
        BigInteger numerator = BigInteger.valueOf(10);
        BigInteger denominator = BigInteger.valueOf(2);

        for (int i = 1; i <= n; i++) {
            BigInteger factorial = BigInteger.valueOf(1);
            for (int j = 1; j <= i * 2; j++) {
                factorial = factorial.multiply(BigInteger.valueOf(j));
            }
            sum = sum.add(numerator.divide(denominator.multiply(factorial)));
            numerator = numerator.multiply(BigInteger.valueOf(2));
            denominator = denominator.multiply(BigInteger.valueOf(i * 2));
        }

        System.out.println(sum);
    }
}

代码中使用了 `BigInteger` 类型来处理超过 `long` 类型范围的大数运算。运行程序后，输入任意正整数 `n`，即可得到公式的计算结果。