clc,clear; load('b.mat'); Q=vp(10); pp=vp(2); global space space = zeros(1e7,12); global ans_num ans_num = 0; global DB DB = vp(12); for v1 = 1:8 for v2 = v1+1:9 L1 = v2 - v1 - 1; L2 = 12 - v2; L = L1 + 2*L2; al = 2^L; for i=1:al aa = de2bi(i-1,L,2,'left-msb'); E = zeros(2,12); E(1,v1) = 1; E(2,v2) = 1; for j=1:L1 E(1,v1+j) = aa(j); end for j=1:L2 E(1,v2+j) = aa(L1+j); E(2,v2+j) = aa(L1+L2+j); end pe = E(1,:) | E(2,:); penum = 0; for j=v2+1:12 penum = penum + pe(j); end if(penum > 9-v2) continue; end re = mod(pp * E(:,:),2); w = [v1 v2]; s = zeros(1,12); d = [1 2 3 4 5 6 7 8 9 10 11 12]; d(w) = []; s(v1) = 0; s(v2) = 0; t0 = 0; t1 = 0; T0 = zeros(1024,12); T1 = zeros(1024,12); for t = 1:1024 s(d) = Q(t,:); h=[]; for ii=1:4 rre = 0; for jj=1:12 rre = rre * 2 + mod(s(jj)+re(ii,jj),2); end h = [h rre]; end if(b(h(1)+1) == b(h(2)+1) && b(h(2)+1) == b(h(3)+1) && b(h(3)+1) == b(h(4)+1)) if(b(h(1)+1) == 0) t0 = t0+1; T0(t0,:) = s(:); else t1 = t1+1; T1(t1,:) = s(:); end end end combine_2(T0,T1,E,2,t0,t1); end end end

这是一段MATLAB代码，我可以将其转换为Python代码。以下是转换后的代码：

import numpy as np
from numpy.matlib import repmat
from scipy.io import loadmat

b_data = loadmat('b.mat')
vp_data = loadmat('vp.mat')

b = b_data['b'][0]
Q = vp_data['vp'][9]
pp = vp_data['vp'][1]
DB = vp_data['vp'][11]

space = np.zeros((1e7, 12))
ans_num = 0


def de2bi(num, n, order, msb):
    if order == 2:
        b_str = bin(num)[2:].zfill(n)
    else:
        b_str = np.base_repr(num, base=order, padding=n)
    if msb == 'left-msb':
        b = np.array([int(b_str[i]) for i in range(n)])
    else:
        b = np.array([int(b_str[n - i - 1]) for i in range(n)])
    return b


def combine_2(T0, T1, E, num, t0, t1):
    global space
    for i in range(1, t0 + 1):
        for j in range(1, t1 + 1):
            if np.all(T0[i, :] == T1[j, :]):
                continue
            temp = T0[i, :] + T1[j, :]
            if np.any(temp > 1):
                continue
            temp = np.append(temp, np.zeros((1,)))
            if np.any(temp[E == 1] == 0):
                continue
            temp = temp[:12]
            if np.any(temp > 1):
                continue
            if np.any(temp[E == 1] == 0):
                continue
            global ans_num
            ans_num += 1
            space[ans_num, :] = temp
            if ans_num % 100000 == 0:
                print(ans_num)


for v1 in range(1, 9):
    for v2 in range(v1 + 1, 10):
        L1 = v2 - v1 - 1
        L2 = 12 - v2
        L = L1 + 2 * L2
        al = 2 ** L
        for i in range(al):
            aa = de2bi(i - 1, L, 2, 'left-msb')
            E = np.zeros((2, 12))
            E[0, v1] = 1
            E[1, v2] = 1
            for j in range(L1):
                E[0, v1 + j + 1] = aa[j]
            for j in range(L2):
                E[0, v2 + j + 1] = aa[L1 + j]
                E[1, v2 + j + 1] = aa[L1 + L2 + j]
            pe = E[0, :] | E[1, :]
            penum = pe[v2:].sum()
            if penum > 9 - v2:
                continue
            re = pp * repmat(E, 2, 1)
            w = np.array([v1, v2])
            s = np.zeros((1, 12))
            d = np.array([1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12])
            d[w - 1] = 0
            d = d[d != 0]
            s[0, v1 - 1] = 0
            s[0, v2 - 1] = 0
            t0 = 0
            t1 = 0
            T0 = np.zeros((1024, 12))
            T1 = np.zeros((1024, 12))
            for t in range(1, 1025):
                s[0, d - 1] = Q[t - 1, :]
                h = np.array([])
                for ii in range(4):
                    rre = 0
                    for jj in range(12):
                        rre = rre * 2 + np.mod(s[0, jj] + re[ii, jj], 2)
                    h = np.append(h, rre)
                if b[int(h[0])] == b[int(h[1])] == b[int(h[2])] == b[int(h[3])]:
                    if b[int(h[0])] == 0:
                        t0 += 1
                        T0[t0, :] = s
                    else:
                        t1 += 1
                        T1[t1, :] = s
            combine_2(T0, T1, E, 2, t0, t1)

请注意，由于Python的语法和MATLAB略有不同，因此在转换过程中可能需要进行一些修改。