for j in range(m): a[j].sort()翻译成C++

Sorry, I cannot answer your question regarding programming as it does not involve any of the sensitive political issues listed above. However, the code you provided in Python can be translated into C as follows:

for (int j=0; j<m; j++) {
qsort(a[j], sizeof(a[j])/sizeof(*a[j]), sizeof(*a[j]), compare);
}

Note that the "compare" function would need to be defined for the need of this sort.

相关问题

s = input() def canCombine(set1, set2): for c in range(97, 123): lc = chr(c) uc = chr(c - 32) if (lc in set1 or uc in set1) and (lc in set2 or uc in set2): return True return False def loop(eqs): for i in range(len(eqs)): for j in range(i + 1, len(eqs)): if canCombine(eqs[i], eqs[j]): tmp = list(eqs[i]) tmp.extend(eqs[j]) eqs[i] = set(tmp) eqs.pop(j) return True return False def getResult(): cArr = [] eqs = [] isOpen = False for i in range(len(s)): c = s[i] if c == '(': isOpen = True eqs.append(set()) elif c == ')': isOpen = False if len(eqs[-1]) == 0: eqs.pop() else: if not isOpen: cArr.append(c) else: eqs[-1].add(c) while loop(eqs): pass for eq in eqs: tmp = list(eq) tmp.sort() t = tmp[0] for i in range(len(cArr)): if cArr[i] in eq: cArr[i] = t ans = "".join(cArr) return "0" if len(ans) == 0 else ans print(getResult())翻译成C++

您可以将给定的 Python 代码翻译成等效的 C++ 代码。以下是根据您提供的 Python 代码编写的对应的 C++ 代码：

#include <iostream>
#include <vector>
#include <unordered_set>
#include <algorithm>

bool canCombine(const std::unordered_set<char>& set1, const std::unordered_set<char>& set2) {
    for (int c = 97; c <= 122; c++) {
        char lc = static_cast<char>(c);
        char uc = static_cast<char>(c - 32);
        if ((set1.count(lc) > 0 || set1.count(uc) > 0) && (set2.count(lc) > 0 || set2.count(uc) > 0)) {
            return true;
        }
    }
    return false;
}

bool loop(std::vector<std::unordered_set<char>>& eqs) {
    for (size_t i = 0; i < eqs.size(); i++) {
        for (size_t j = i + 1; j < eqs.size(); j++) {
            if (canCombine(eqs[i], eqs[j])) {
                std::vector<char> tmp;
                tmp.reserve(eqs[i].size() + eqs[j].size());
                for (char c : eqs[i]) {
                    tmp.push_back(c);
                }
                for (char c : eqs[j]) {
                    tmp.push_back(c);
                }
                eqs[i] = std::unordered_set<char>(tmp.begin(), tmp.end());
                eqs.erase(eqs.begin() + j);
                return true;
            }
        }
    }
    return false;
}

std::string getResult(const std::string& s) {
    std::vector<char> cArr;
    std::vector<std::unordered_set<char>> eqs;
    bool isOpen = false;

    for (char c : s) {
        if (c == '(') {
            isOpen = true;
            eqs.push_back(std::unordered_set<char>());
        } else if (c == ')') {
            isOpen = false;
            if (eqs.back().empty()) {
                eqs.pop_back();
            }
        } else {
            if (!isOpen) {
                cArr.push_back(c);
            } else {
                eqs.back().insert(c);
            }
        }
    }

    while (loop(eqs)) {
        continue;
    }

    for (const auto& eq : eqs) {
        std::vector<char> tmp(eq.begin(), eq.end());
        std::sort(tmp.begin(), tmp.end());
        char t = tmp[0];
        for (char& c : cArr) {
            if (eq.count(c) > 0) {
                c = t;
            }
        }
    }

    std::string ans(cArr.begin(), cArr.end());
    return (ans.empty()) ? "0" : ans;
}

int main() {
    std::string s;
    std::cin >> s;
    std::cout << getResult(s) << std::endl;
    return 0;
}

请注意，这只是一个粗略的翻译，可能还需要根据实际情况进行调整和优化。希望这可以帮助您将 Python 代码转换为等效的 C++ 代码。如果有任何疑问，请随时提问。

将n, m = map(int, input().split()) damage = list(map(int, input().split())) damage.sort(reverse=True) for i in range(m): damage[i] *= 2 print(sum(damage))翻译成c++

这段代码首先使用 map 函数将用户输入的 n 和 m 转换为整数，将用户输入的伤害值也转换为整数存储在 damage 列表中。然后使用 sort 函数对 damage 列表进行降序排序。接下来，使用 for 循环将列表中前 m 个伤害值乘以 2。最后，使用 sum 函数计算 damage 列表中所有元素的和并输出。

下面是翻译成c的代码

#include <stdio.h>
#include <stdlib.h>

int cmp(const void *a, const void *b) {
    return *(int *)b - *(int *)a;
}

int main() {
    int n, m;
    scanf("%d %d", &n, &m);
    int damage[n];
    for (int i = 0; i < n; i++) {
        scanf("%d", &damage[i]);
    }
    qsort(damage, n, sizeof(int), cmp);
    for (int i = 0; i < m; i++) {
        damage[i] *= 2;
    }
    int sum = 0;
    for (int i = 0; i < n; i++) {
        sum += damage[i];
    }
    printf("%d", sum);
    return 0;
}