error: cannot bind 'std::basic_ostream<char>' lvalue to 'std::basic_ostream<char>&&' std::cout << "Value *strideCoeff = " << *strideCoeff <<std::endl;是什么意思
这个错误通常是因为你在使用 std::cout
对象时,将其绑定到了一个右值上。在 C++11 中,移动语义被引入到语言中,允许将临时对象绑定到非常量左值引用中。因此,当你尝试将 std::cout
对象绑定到右值时,编译器会尝试将其转换为一个右值引用,但是这个转换是不允许的,所以编译器会抛出上述错误。
在你的代码中,出现这个错误的原因可能是因为你使用了一个不支持左值引用的表达式,比如一个临时对象或一个函数返回值。解决这个问题的方法是将 std::cout
对象绑定到一个左值上,比如一个变量或表达式的结果。你可以将代码修改为:
std::cout << "Value *strideCoeff = " << *strideCoeff << std::endl;
这样就可以将 std::cout
对象绑定到一个左值上,并且不会出现上述错误。需要注意的是,std::endl
是一个函数模板,你需要在名称后面添加一个尖括号来指定模板参数。
[Error] cannot bind 'std::ostream {aka std::basic_ostream<char>}' lvalue to 'std::basic_ostream<char>&&'
这个错误是因为尝试将一个左值绑定到一个右值引用上,具体来说是尝试将一个 std::ostream 对象绑定到一个 std::basic_ostream
[Error] cannot bind ‘std::ostream {aka std::basic_ostream<char>}‘ l value To'std::basic_ostream<char>&&'
This error message means that you are trying to assign a value to an output stream (std::ostream) using an lvalue (an expression that refers to an object that has a memory address) but the type of the lvalue is not compatible with the type of the output stream.
For example, if you have the following code:
int main() {
int x = 42;
std::ostream out;
out = x;
return 0;
}
You will get the error message because you cannot assign an integer value to an output stream. You need to use the insertion operator (<<) to write the value to the stream:
int main() {
int x = 42;
std::ostream out;
out << x;
return 0;
}
This will write the value of x to the output stream.
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