利用Java语言,实现虚拟内存的页面置换LRU算法
时间: 2024-02-17 19:02:21 浏览: 66
好的,下面是Java实现虚拟内存的页面置换LRU算法的示例代码:
```java
import java.util.*;
public class LRUPageReplacement {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("请输入内存块大小: ");
int frames = sc.nextInt();
int pointer = 0, hit = 0, fault = 0;
int[] buffer = new int[frames];
boolean[] flag = new boolean[frames];
ArrayList<Integer> stack = new ArrayList<Integer>();
for(int i = 0; i < frames; i++) {
buffer[i] = -1;
flag[i] = false;
}
System.out.print("请输入要访问的页面序列 (以 -1 结束): ");
int victim = sc.nextInt();
while(victim != -1) {
if(Arrays.asList(buffer).contains(victim)) {
hit++;
stack.remove(stack.indexOf(victim));
stack.add(victim);
}
else {
if(flag[pointer]) {
int replace = stack.get(0);
stack.remove(0);
for(int i = 0; i < frames; i++) {
if(buffer[i] == replace) {
buffer[i] = victim;
}
}
stack.add(victim);
}
else {
buffer[pointer] = victim;
flag[pointer] = true;
stack.add(victim);
}
pointer++;
fault++;
if(pointer == frames) {
pointer = 0;
}
}
System.out.print("内存块状态:");
for(int i = 0; i < frames; i++) {
System.out.print(buffer[i] + " ");
}
System.out.println();
System.out.print("请输入要访问的页面序列 (以 -1 结束): ");
victim = sc.nextInt();
}
System.out.println("缺页次数: " + fault);
System.out.println("命中次数: " + hit);
System.out.println("缺页率: " + (float) fault / (hit + fault));
sc.close();
}
}
```
在该示例代码中,LRU算法使用了一个栈来保存最近使用的页面的顺序。当发生缺页时,将栈底的页面替换成新的页面。如果内存块已满,则将栈底页面替换成新页面,并将该页面移动到栈顶。
同时,程序还输出了缺页次数、命中次数和缺页率等信息,方便统计和分析算法的性能。
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