用python写一个解数独的程度
时间: 2024-05-06 22:21:48 浏览: 17
好的,我可以为您提供一个基于Python的解数独程序,您可以使用以下代码:
```python
def isValid(board, row, col, num):
# Check row
for i in range(9):
if board[row][i] == num:
return False
# Check column
for i in range(9):
if board[i][col] == num:
return False
# Check square
startRow = (row // 3) * 3
startCol = (col // 3) * 3
for i in range(startRow, startRow + 3):
for j in range(startCol, startCol + 3):
if board[i][j] == num:
return False
return True
def solveSudoku(board):
for row in range(9):
for col in range(9):
if board[row][col] == '.':
for num in range(1, 10):
if isValid(board, row, col, str(num)):
board[row][col] = str(num)
if solveSudoku(board):
return True
board[row][col] = '.'
return False
return True
```
这个程序使用了回溯算法来解决数独问题。它通过逐个尝试填充每个空单元格,如果填充的数值有效,则继续填充下一个单元格。如果无法填充,则执行回溯并尝试另一个值。最终,当所有单元格都填满时,数独得以解决。
运行程序的方式是,使用一个9x9的矩阵来表示数独游戏的初始状态。空单元格应该表示为一个点“.”。例如,以下代码将数独谜题输入程序中并得到解决方案:
```python
board = [
["5","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
solveSudoku(board)
for row in board:
print(row)
```
您可以将此代码复制并运行,并将其适当调整来解决您的数独问题。希望能帮到您!