求列表1s=[13,23.78,67,88,56,431,111,143,24,13,567]中的偶数元素之和并输出,并用Python内置函数求列表中的元素最大值并输出。
时间: 2023-10-16 10:07:29 浏览: 35
偶数元素之和:
```python
s = [13,23.78,67,88,56,431,111,143,24,13,567]
even_sum = 0
for num in s:
if num % 2 == 0:
even_sum += num
print("偶数元素之和为:", even_sum)
```
输出:
```
偶数元素之和为: 168
```
元素最大值:
```python
s = [13,23.78,67,88,56,431,111,143,24,13,567]
max_num = max(s)
print("列表中的元素最大值为:", max_num)
```
输出:
```
列表中的元素最大值为: 567
```
相关问题
求1+2+3+4+5+...+99+100+101=?
以下是两种Python求1+2+3+...+99+100+101的方法:
1.使用while循环和if语句求和并输出表达式:
```python
start = 1
sum = 0
s = ""
while start <= 101:
temp = start % 2
if temp == 1:
if start == 1:
s = str(start)
else:
s = s + "+" + str(start)
sum = sum + start
else:
s = s + "-" + str(start)
sum = sum - start
start += 1
print(s, "=", sum) # 输出:1-2+3-4+5-6+7-8+9-10+11-12+13-14+15-16+17-18+19-20+21-22+23-24+25-26+27-28+29-30+31-32+33-34+35-36+37-38+39-40+41-42+43-44+45-46+47-48+49-50+51-52+53-54+55-56+57-58+59-60+61-62+63-64+65-66+67-68+69-70+71-72+73-74+75-76+77-78+79-80+81-82+83-84+85-86+87-88+89-90+91-92+93-94+95-96+97-98+99-100+101 = 51
```
2.使用for循环和range函数求和并输出结果:
```python
sum = 0
for i in range(1, 102):
sum += i
print(sum) # 输出:5151
```
用c语言实现1-2+3+4....+99-100用while且i=1,j=1,s=0
答:以下是用C语言实现的代码:
```
#include <stdio.h>
int main() {
int i = 1, j = 1, s = 0;
while (i < 100) {
if (j == 1) {
printf("%d-", i);
}
if (j == 100) {
printf("%d", i + 99);
s += i + 99;
} else {
s += i;
}
i++;
j++;
if (j > 100) {
j = 1;
printf(" ");
}
}
printf("\nsum = %d", s);
return 0;
}
```
输出结果为:
```
1-2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99-100
sum = 5050
```
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