求1+2+3+4+5+...+99+100+101=?
时间: 2023-12-14 17:32:36 浏览: 100
以下是两种Python求1+2+3+...+99+100+101的方法:
1.使用while循环和if语句求和并输出表达式:
```python
start = 1
sum = 0
s = ""
while start <= 101:
temp = start % 2
if temp == 1:
if start == 1:
s = str(start)
else:
s = s + "+" + str(start)
sum = sum + start
else:
s = s + "-" + str(start)
sum = sum - start
start += 1
print(s, "=", sum) # 输出:1-2+3-4+5-6+7-8+9-10+11-12+13-14+15-16+17-18+19-20+21-22+23-24+25-26+27-28+29-30+31-32+33-34+35-36+37-38+39-40+41-42+43-44+45-46+47-48+49-50+51-52+53-54+55-56+57-58+59-60+61-62+63-64+65-66+67-68+69-70+71-72+73-74+75-76+77-78+79-80+81-82+83-84+85-86+87-88+89-90+91-92+93-94+95-96+97-98+99-100+101 = 51
```
2.使用for循环和range函数求和并输出结果:
```python
sum = 0
for i in range(1, 102):
sum += i
print(sum) # 输出:5151
```
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