vhdl语言的八路抢答器
时间: 2023-07-27 21:05:46 浏览: 110
以下是一个简单的八路抢答器的 VHDL 代码实现,可以参考:
```vhdl
entity quizmaster is
port(clk : in std_logic;
reset : in std_logic;
question : in std_logic_vector(7 downto 0);
q_valid : in std_logic;
buzzer : in std_logic_vector(7 downto 0);
answer : out std_logic_vector(2 downto 0);
a_valid : out std_logic);
end quizmaster;
architecture Behavioral of quizmaster is
signal q_counter : integer range 0 to 7 := 0;
signal reset_flag : std_logic := '0';
signal question_flag : std_logic := '0';
signal buzzer_flag : std_logic_vector(7 downto 0) := (others => '0');
signal buzzer_winner : integer range 0 to 7 := -1;
signal buzzer_pressed : std_logic_vector(7 downto 0) := (others => '0');
signal answer_flag : std_logic := '0';
signal answer_value : integer range 0 to 7 := -1;
begin
process(clk, reset)
begin
if reset = '1' then
q_counter <= 0;
reset_flag <= '1';
question_flag <= '0';
buzzer_flag <= (others => '0');
buzzer_winner <= -1;
buzzer_pressed <= (others => '0');
answer_flag <= '0';
answer_value <= -1;
elsif rising_edge(clk) then
reset_flag <= '0';
if q_valid = '1' and question_flag = '0' then
question_flag <= '1';
q_counter <= 0;
end if;
if question_flag = '1' then
if q_counter = 7 then
question_flag <= '0';
buzzer_flag <= (others => '1');
else
q_counter <= q_counter + 1;
end if;
end if;
for i in 0 to 7 loop
if buzzer(i) = '1' and buzzer_flag(i) = '1' and buzzer_pressed(i) = '0' then
buzzer_winner <= i;
buzzer_pressed(i) <= '1';
buzzer_flag(i) <= '0';
end if;
end loop;
if buzzer_winner /= -1 and answer_flag = '0' then
answer_flag <= '1';
answer_value <= buzzer_winner;
end if;
if a_valid = '1' and answer_flag = '1' then
answer_flag <= '0';
buzzer_winner <= -1;
buzzer_pressed <= (others => '0');
answer_value <= -1;
end if;
end if;
end process;
answer <= std_logic_vector(to_unsigned(answer_value, 3));
a_valid <= answer_flag;
end Behavioral;
```
本代码实现了一个基本的八路抢答器,它包括一个计数器,用于控制问答环节的进行;一个状态机,用于控制整个抢答的流程;一个标志位,用于表示当前是否有人按下了按钮;一个数组,用于记录每个参赛者是否按下了按钮;以及一个标志位和一个变量,用于记录当前获胜者和回答正确的参赛者。
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