用C语言建立很有十个节点的单链表

可以使用以下代码建立一个有十个节点的单链表：

#include <stdio.h>
#include <stdlib.h>

struct Node {
    int data;
    struct Node* next;
};

int main() {
    struct Node* head = NULL;
    struct Node* tail = NULL;

    // 创建十个节点
    for (int i = 1; i <= 10; i++) {
        struct Node* newNode = (struct Node*)malloc(sizeof(struct Node));
        newNode->data = i;
        newNode->next = NULL;

        if (head == NULL) {
            head = newNode;
            tail = newNode;
        } else {
            tail->next = newNode;
            tail = newNode;
        }
    }

    // 遍历链表并输出每个节点的值
    struct Node* current = head;
    while (current != NULL) {
        printf("%d ", current->data);
        current = current->next;
    }

    return 0;
}

这段代码会创建一个有十个节点的单链表，并输出每个节点的值。