matlab对五杆机构进行轨迹规划的代码
时间: 2023-06-14 08:06:35 浏览: 186
轨迹规划matlab源代码.zip
五杆机构的轨迹规划可以采用逆向求解的方法,即已知末端执行器的轨迹,求解五杆机构各个连杆的角度轨迹。下面是一个基于MATLAB的五杆机构轨迹规划代码示例:
```matlab
% 五杆机构轨迹规划
% 假设五杆机构的长度为:a1、a2、a3、a4、a5
% 已知末端执行器的轨迹,以x、y坐标表示
x = linspace(0, 10, 100); % x轴坐标
y = sin(x); % y轴坐标
% 求解各个连杆的角度
for i = 1:length(x)
% 求解连杆4的角度
a = 2 * a2 * (x(i) + a5 * cos(y(i))) - 2 * a1 * (y(i) - a5 * sin(y(i)));
b = 2 * a2 * (y(i) - a5 * sin(y(i))) - 2 * a1 * (x(i) + a5 * cos(y(i)));
c = a^2 + b^2 + 2 * a * b * cos(pi - acos((a3^2 + a^2 + b^2 - a4^2) / (2 * a3 * sqrt(a^2 + b^2)))));
theta4(i) = pi - acos((a3^2 + a4^2 - c) / (2 * a3 * a4));
% 求解连杆3的角度
theta3(i) = atan2(b, a) - atan2(a4 * sin(theta4(i)), a3 + a4 * cos(theta4(i)));
% 求解连杆2的角度
theta2(i) = atan2(y(i) - a5 * sin(y(i)) - a1 * sin(theta3(i)), x(i) + a5 * cos(y(i)) + a1 * cos(theta3(i))) - atan2(a3 * sin(theta3(i)), a2 + a3 * cos(theta3(i)));
% 求解连杆1的角度
theta1(i) = atan2(y(i) - a5 * sin(y(i)) - a2 * sin(theta2(i)) - a3 * sin(theta3(i)), x(i) + a5 * cos(y(i)) + a2 * cos(theta2(i)) + a3 * cos(theta3(i)));
% 求解连杆5的角度
theta5(i) = y(i) - theta1(i) - theta2(i) - theta3(i) - theta4(i);
end
% 绘制五杆机构的轨迹图
figure;
plot(x, y);
hold on;
axis equal;
for i = 1:length(x)
plot([0, a1 * cos(theta1(i)), a1 * cos(theta1(i)) + a2 * cos(theta1(i) + theta2(i)), a1 * cos(theta1(i)) + a2 * cos(theta1(i) + theta2(i)) + a3 * cos(theta1(i) + theta2(i) + theta3(i)), a1 * cos(theta1(i)) + a2 * cos(theta1(i) + theta2(i)) + a3 * cos(theta1(i) + theta2(i) + theta3(i)) + a4 * cos(theta1(i) + theta2(i) + theta3(i) + theta4(i)), a1 * cos(theta1(i)) + a2 * cos(theta1(i) + theta2(i)) + a3 * cos(theta1(i) + theta2(i) + theta3(i)) + a4 * cos(theta1(i) + theta2(i) + theta3(i) + theta4(i)) + a5 * cos(y(i))], [0, a1 * sin(theta1(i)), a1 * sin(theta1(i)) + a2 * sin(theta1(i) + theta2(i)), a1 * sin(theta1(i)) + a2 * sin(theta1(i) + theta2(i)) + a3 * sin(theta1(i) + theta2(i) + theta3(i)), a1 * sin(theta1(i)) + a2 * sin(theta1(i) + theta2(i)) + a3 * sin(theta1(i) + theta2(i) + theta3(i)) + a4 * sin(theta1(i) + theta2(i) + theta3(i) + theta4(i)), a1 * sin(theta1(i)) + a2 * sin(theta1(i) + theta2(i)) + a3 * sin(theta1(i) + theta2(i) + theta3(i)) + a4 * sin(theta1(i) + theta2(i) + theta3(i) + theta4(i)) + a5 * sin(y(i))]);
end
```
需要注意的是,五杆机构的轨迹规划是一个相对复杂的问题,需要对机构的各个连杆的长度、角度等参数有深入的了解。此处仅提供了一个简单的示例代码,供参考。
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