return HttpResponseRedirect(reverse('history')) reverse() takes exactly 2 arguments (1 given)如何修改
时间: 2023-11-28 14:06:33 浏览: 32
`reverse()`函数需要传入一个路由名称作为参数,如果路由中需要传入参数,则需要在参数后面传入对应的值。如果报错提示中说只给了一个参数,那么很可能是因为没有传入路由名称或者路由名称写错了。
在这个情况下,你需要检查一下传入的参数是否正确。如果你确认传入的参数正确,但是依然报错,那么可能是因为你没有正确导入`reverse`函数,你需要在文件开头加上`from django.urls import reverse`。如果还有问题,请提供更多代码和报错信息,以便我能够更好地帮助你。
相关问题
def reverse_string(s): return s[::-1]
As an AI language model, I do not have the context to identify the problem this code is trying to solve. However, I can tell you that this function takes a string as an argument and returns the reversed version of that string using the slicing technique in Python.
In Python, strings can be sliced using the syntax s[start:stop:step], where start is the starting index of the slice, stop is the stopping index of the slice, and step is the step size for the slice. If any of these values are not specified, they default to their default values, which are 0 for start, len(s) for stop, and 1 for step.
In this function, the slicing syntax s[::-1] is used to reverse the string. The start and stop values are omitted, which means the slice will start from the beginning and go all the way to the end of the string. The step value is -1, which means the slice will go from the end of the string to the beginning, effectively reversing the string.
t1=(1,2,3,4)display t1 in reverse order
To display the tuple t1 in reverse order, you can use the following code:
```python
t1 = (1, 2, 3, 4)
t1_reversed = tuple(reversed(t1))
print(t1_reversed)
```
This will output:
```
(4, 3, 2, 1)
```
Here, we first create the tuple `t1` with the values `(1, 2, 3, 4)`. Then, we use the `reversed()` function to reverse the order of the tuple, which returns a reverse iterator object. We convert this iterator object back to a tuple using the `tuple()` constructor, and store it in a new variable `t1_reversed`. Finally, we print the reversed tuple using the `print()` function.