编写程序实现两个整数集合的基本运算： S1+S2 集合并运算 S1-S2 集合差运算 S1*S2 集合交运算 要求：输入整数集合{2 4 1 3 5}和{2 5 10}，输出前者元素个数以及它们进行集合并、差、交运算后的结果。用c++运算符重载实现

下面是代码示例：

#include <iostream>
#include <set>
using namespace std;

class Set {
private:
    set<int> s;

public:
    Set() {}
    Set(initializer_list<int> list) {
        for (auto x : list) {
            s.insert(x);
        }
    }

    int size() const {
        return s.size();
    }

    Set operator+(const Set& other) const {
        Set result;
        for (auto x : s) {
            result.s.insert(x);
        }
        for (auto x : other.s) {
            result.s.insert(x);
        }
        return result;
    }

    Set operator-(const Set& other) const {
        Set result;
        for (auto x : s) {
            if (other.s.find(x) == other.s.end()) {
                result.s.insert(x);
            }
        }
        return result;
    }

    Set operator*(const Set& other) const {
        Set result;
        for (auto x : s) {
            if (other.s.find(x) != other.s.end()) {
                result.s.insert(x);
            }
        }
        return result;
    }

    friend ostream& operator<<(ostream& os, const Set& set) {
        os << "{";
        for (auto x : set.s) {
            os << x << ", ";
        }
        os << "}";
        return os;
    }
};

int main() {
    Set s1{2, 4, 1, 3, 5};
    Set s2{2, 5, 10};
    cout << "s1 size: " << s1.size() << endl;
    cout << "s2 size: " << s2.size() << endl;
    cout << "s1 + s2 = " << s1 + s2 << endl;
    cout << "s1 - s2 = " << s1 - s2 << endl;
    cout << "s1 * s2 = " << s1 * s2 << endl;
    return 0;
}

输出结果为：

s1 size: 5
s2 size: 3
s1 + s2 = {1, 2, 3, 4, 5, 10, }
s1 - s2 = {1, 3, 4, }
s1 * s2 = {2, 5, }